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3 years ago

An object with a higher temperature can have less thermal energy than an object

1 answer:

4 0

It’s true, because it also depends on things like mass. Higher temperature but less mass< Lower temperature but more mass.

You might be interested in

You would convert from grams to moles by using the ___________ of the substance.

Firdavs [7]

You would convert from grams to moles by using the molar mass of the substance. The answer is letter B. for example, the molar mass Carbon dioxide is 44.01 g/mol. It means that for 1 mole of carbon dioxide, it contains 44.01 grams of Carbon dioxide.

7 0

3 years ago

Three identical train cars, coupled together are rolling east at 2.0 m/s. A fourth car traveling east at 4.0 m/s catches up with

Ann [662]

Answer:

The value is $v = 2 \ m/s$

Explanation:

From the question we are told that

The velocity of the each of the three cars is $u_1 = u_2 = u_3 = 2 \ m/s$

The velocity of the fourth car is $u_4 = 4 \ m/s$

The initial velocity of the fifth car $u_5 = 0 \ m/s$

Generally from the law of momentum conservation we have that

$m_1 u_1 + m_2 u_2 + m_3 u_3 +m_4u_4 + m_5u_5 = [m_1 + m_2 + m_3 +m_4+ m_5]v$

Given that the cars are identical then their mass will be the same

i.e

$m_1 =m_2 = m_3 = m_4 = m_5 = m$

=> $[u_1 + u_2 + u_3 +u_4 + u_5]m = 5mv$

=> $2+ 2 + 2 +4 + 0 = 5v$

= > $v = 2 \ m/s$

8 0

3 years ago

A small block with mass 0.0350 kgkg slides in a vertical circle of radius 0.550 mm on the inside of a circular track. During one

Lisa [10]

Answer:

W_net = μ 5.58, μ = 0.1 W_net = 0.558 J

Explanation:

The work is defined by the related

W = F. d = F d cos θ

where bold indicates vectors.

In the case, the work of the friction force on a circular surface is requested.

The expression for the friction force is

fr = μ N

the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1

W = - fr d

the path traveled half the length of the circle

L = 2 π R

d = L / 2

d = π R

we substitute

W = - μ N d

Total work is initial to

W_neto = - μ π R (N_b - N_a)

let's calculate

W_net = - μ π 0.550 (0.670 - 3.90)

W_net = μ 5.58

for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1

W_net = 0.1 5.58

W_net = 0.558 J

7 0

3 years ago

A 111 kg 111 kg horizontal platform is a uniform disk of radius 1.67 m 1.67 m and can rotate about the vertical axis through its

Mashcka [7]

Answer:

287.19 kg.m²

Explanation:

Given that :

The mass M of the horizontal platform = 111 kg

The radius R of the uniform disk = 1.67 m

mass of the person standing $m_p$ = 64.7 kg

distance of the person standing $d_p$ = 1.15 m

mass of the dog $m_d$ = 25.7 kg

distance of the dog $d_d$ = 1.35 m

Considering the moment of inertia of the object in the system; the net moment of the inertia can be expressed as:

= $\frac{MR^2}{2}+m_pd_p^2+m_dd_d^2$

= $(\frac{111*1.67^2}{2})+ (64.7 *1.15^2)+ (25.7*1.35^2)$

= 287.19 kg.m²

5 0

4 years ago

While rowing in a race, John uses his arms to exert a force of 155 N per stroke

Basile [38]

Answer:

Workdone = 2906.25J

Explanation:

Given the following data;

Force, F = 155

Distance, d = 0.75

Stroke, s = 25

Mathematically, work done is given by the formula;

Work done = force * distance * stroke

$W = F * d * s$

Where,

W is the work done

F represents the force acting on a body.

d represents the distance covered by the body.

s is the number of strokes.

Substituting into the equation, we have;

$Workdone = 155*0.75*25$

Workdone = 2906.25J

6 0

3 years ago