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3 years ago

An object with a higher temperature can have less thermal energy than an object

1 answer:

4 0

It’s true, because it also depends on things like mass. Higher temperature but less mass< Lower temperature but more mass.

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Two parallel-plate capacitors have the same dimensions, but the space between the plates is filled with air in capacitor 1 and w

Aleks [24]

Explanation:

The capacitance in two parallel-plate capacitors is:

$C=\frac{K\epsilon_oA}{d}$

For air, we have $K_1=1$

For plastic, we have $K_2=2.25$

Hence:

$C_1=\frac{K_1\epsilon_oA}{d_1}=\frac{\epsilon_oA}{d_1}\\C_2=\frac{K_2\epsilon_oA}{d_2}=2.25(\frac{\epsilon_oA}{d_2})$

a) Recall that the potential difference between the plates is the same ( $V_1=V_2=V$ ). The electric field is given by:

$E_1=\frac{V_1}{d_1}=\frac{V}{d_1}\\E_2=\frac{V_2}{d_2}=\frac{V}{d_1}$

The potential difference is defined as:

$V_1=\frac{Q_1}{C_1}=V\\V_2=\frac{Q_2}{C_2}=V$

Replacing:

$E_1=\frac{Q_1}{C_1d_1}\\E_2=\frac{Q_1}{C_1d_2}\\\\E_1d_1=\frac{Q_1}{C_1}\\E_2d_2=\frac{Q_1}{C_1}\\E_1d_1=E_2d_2\\\frac{E_1}{E_2}=\frac{d_2}{d_1}$

b) The energy is defined as:

$U=\frac{1}{2}CV^2$

So:

$U_1=\frac{1}{2}C_1V_1^2=\frac{1}{2}C_1V^2\\U_2=\frac{1}{2}C_2V_2^2=\frac{1}{2}C_2V^2\\U_1=\frac{1}{2}\frac{\epsilon_oA}{d_1}V^2\\U_2=\frac{1}{2}\frac{2.25\epsilon_oA}{d_2}V^2\\\frac{0.88U_2d_2}{\epsilon_oA}=V^2\\\frac{2U_1d_1}{\epsilon_oA}=V^2\\\frac{0.88U_2d_2}{\epsilon_oA}=\frac{2U_1d_1}{\epsilon_oA}\\\frac{U_1}{U_2}=0.44\frac{d_2}{d_1}$

5 0

3 years ago

True or false: Decreased output from the vasomotor center allows arterioles and veins to constrict.

wolverine [178]

<h3><u>Answer;</u></h3>

The above statement is False

<h3><u>Explanation;</u></h3>

Decreased output from the vasomotor center allows arterioles and veins to dilate.
The vasomotor center controls vessel tone or contraction of the smooth muscle in the tunica media.It is responsible for central regulation of cardiac electrical activity, myocardial performance, and peripheral vascular tone.
Changes in diameter affect peripheral resistance, pressure, and flow, which in turn affect cardiac output.

3 0

3 years ago

This graph shows a ball rolling from A to G. The ball starts at point A and rolls to point G.

Lerok [7]

11. B

12. A

13. D

14. The ball burnt off energy while rolling, it lost potential energy and couldn't go as high.

4 0

3 years ago

The time that is required for a vibrating object to complete one full cycle is called : Group of answer choices

disa [49]

Answer:

Correct option : (c) period.

Explanation:

The time that is required for a vibrating object to complete one full cycle is called the time period. If f is the frequency of a wave, then the relation between the frequency and the time period is given by :

$T=\dfrac{1}{f}$

These are the characteristics of a wave. Some other characteristics are wavelength, amplitude, intensity etc. So, the correct option is (c) "period".

4 0

4 years ago

I put +40 points!!!

Aleonysh [2.5K]

Answer:We can solve this using the Law of Conservation of Momentum. If both marbles are in our system, the initial momentum should equal the final momentum.

The initial momentum can be solved for as so:

* + =

(0.06)(0.7) + (0.03)(0) = 0.042 [kg * m/s]

So if the system has an initial momentum of 0.042, it should have the same final momentum.

(0.06)(-0.2) + (0.03)() = 0.042

(0.03)() = 0.54

() = 18 [m/s]

Explanation:

5 0

3 years ago

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