Ask question

Ask question

All categories

Alekssandra [29.7K]

3 years ago

6

In a decompostion reaction, the reaction decays 21.2 times more rapidly at 22°C then at 4 °C. What is the overall activation ene

rgy (kJ/mol) of the process ?

1 answer:

Murljashka [212]3 years ago

5 0

Explanation:

The given data is as follows.

$T_{1} = 4^{o}C$ = (4 + 273) K = 277 K

$T_{2} = 22^{o}C$ = (22 + 273) K = 295 K

$\frac{k_{2}}{k_{1}}$ = 21.2

Formula to calculate activation energy will be as follows.

$ln \frac{k_{2}}{k_{1}} = \frac{E_{a}}{R} [\frac{1}{T_{1}} - \frac{1}{T_{2}}]$

$ln (21.2) = \frac{E_{a}}{8.314 J/mol K} [\frac{1}{277} - \frac{1}{295}]$

3.05 = $\frac{E_{a}}{8.314 J/mol K} \times \frac{18}{81715}$

$E_{a}$ = 115116.914 J/mol

or = 115.116 kJ/mol

Thus, we can conclude that overall activation energy (kJ/mol) of the process is 115.116 kJ/mol.

You might be interested in

A skydiver jumps out of a hovering helicopter. A few seconds later, another diver jumps out, so they both fall along the same ve

Sergio039 [100]

Answer:

distance difference would a) increase

speed difference would f) stay the same

Explanation:

Let t be the time the 2nd skydiver takes to travel, since the first skydiver jumped first, his time would be t + Δt where Δt represent the duration between the the first skydiver and the 2nd one. Remember that as t progress (increases), Δt remain constant.

Their equations of motion for distance and velocities are

$s_2 = gt^2/2$

$s_1 = g(t + \Delta t)^2/2$

$v_2 = gt$

$v_1 = g(t + \Delta t)$

Their difference in distance are therefore:

$\Delta s = s_1 - s_2 = g(t + \Delta t)^2/2 - gt^2/2$

$\Delta s = g/2((t + \Delta t)^2 - t^2)$

$\Delta s = g/2(t + \Delta t - t)(t + \Delta t + t)$ (As $A^2 - B^2 = (A-B)(A+B)$

$\Delta s = g\Delta t/2(2t + \Delta t)$

So as time progress t increases, Δs would also increases, their distance becomes wider with time.

Similarly for their velocity difference

$\Delta v = v_1 - v_2 = g(t + \Delta t) - gt$

$\Delta v = gt + g\Delta t - gt = g\Delta t$

Since g and Δt both are constant, Δv would also remain constant, their difference in velocity remain the same.

This of this in this way: only the DIFFERENCE in speed stay the same, their own individual speed increases at same rate (due to same acceleration g). But the first skydiver is already at a faster speed (because he jumped first) when the 2nd one jumps. The 1st one would travel more distance compare to the 2nd one in a unit of time.

8 0

3 years ago

Read 2 more answers

It is necessary to determine the specific heat of an unknown object. The mass of the object is 201.0 g. It is determined experim

navik [9.2K]

Mass = 0.201kg
Energy = 15J
temperature change = 10C

Energy(E) = mass(m) × specific heat capacity(c) × temperature change(θ)

we can rearrange this to make specific heat capacity the subject

c = $\frac{E}{m\theta}$

c = $\frac{15}{2.01}$
c =7.46268657

6 0

3 years ago

Read 2 more answers

Countries with traditional economies are often less developed because:

3241004551 [841]

People are resistant to change, People have political freedom, Farmers institute new farming techniques and there is little need for medical facilities.

7 0

3 years ago

Read 2 more answers

Some of the principal minerals commonly found in igneous rocks are

Verdich [7]

I believe that the answer is C. Hope this Helps:)))

3 0

3 years ago

The output voltage of a power supply is normally distributed with mean 5 V and standard deviation 0.02 V. If the lower and upper

-BARSIC- [3]

To solve this problem we will apply the normal distribution, with which we will obtain the probability that the given event will occur. Concepts such as the mean and standard deviation will be present throughout the solution of the problem. Increasing or decreasing the average would change the location or center point of the curve. The change in the standard deviation would lead to the change in the dispersion of the data. As the standard deviation increases, the curve would become flatter.

Let X be the output voltage of power supply

X∼N $(5,0.02^2)$

A

The lower and upper specifications for voltage are 4.95 V and 5.05 V, respectively

$P(4.95$

$P(4.95$

$P(4.95$

$P(4.95$

$P(4.95$

Hence probability that a power supply selected at random will conform to the specifications on voltage is 0.9876

8 0

4 years ago