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harkovskaia [24]
4 years ago
10

A solid disk of mass m1 = 9.3 kg and radius R = 0.22 m is rotating with a constant angular velocity of ω = 31 rad/s. A thin rect

angular rod with mass m2 = 3.9 kg and length L = 2R = 0.44 m begins at rest above the disk and is dropped on the disk where it begins to spin with the disk.
1) What is the initial angular momentum of the rod and disk system?
6.97 kg-m2/s
2) What is the initial rotational energy of the rod and disk system?
108.14 J

3) What is the final angular velocity of the disk?

4) What is the final angular momentum of the rod and disk system?

5) What is the final rotational energy of the rod and disk system?

6) The rod took t = 6.5 s to accelerate to its final angular speed with the disk. What average torque was exerted on the rod by the disk?
Physics
1 answer:
mel-nik [20]4 years ago
5 0
We are given with
<span>m1 = 9.3 kg
R = 0.22 m
ω = 31 rad/s
m2 = 3.9 kg
L = 2R = 0.44 m

The angular momentum is determined using the formula
L  = I w
where I is the moment of inertia

For a solid disk
I = (1/4) MR^2
For a rectangular rod
I = (1/12) ML^2

The rotational energy has the formula
E = (1/2) I w^2

Substitute the given values for getting the answers
</span>
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3 years ago
A particle's velocity is described by the function vx = kt 2 m/s, where k is a constant and t is in s. The particle's position a
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Explanation:

We have the equation of the velocity v_{x} = kt² , where k

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The particle's position at t_{0} = 0 is x_{0} = -9 m

The particle's position at t_{1} = 3 s is x_{1} = 9 m

We need to find the value of the constant k

The relation between the velocity and the displacement in a particular

time is x = \int\ {v_{x} } \, dt

Remember in integration we add power by 1 and divide the expression

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→ x = \int\ {kt^{2} } \, dt=\frac{1}{3}kt^{3}+c

c is the constant of integration to find it substitute the initial value of x

and t in the equation of x

→ t_{0} = 0 , x_{0} = -9 m

→ -9 = \frac{1}{3} k (0)³ + c

→ -9 = c

Substitute the value of c in the equation of x

→ x = \frac{1}{3} k t³ - 9

To find k substitute the values of  t_{1} = 3 s , x_{1} = 9 m

→ 9 = \frac{1}{3} k (3)³ - 9

→ 9 = \frac{1}{3} (27) k - 9

→ 9 = 9 k - 9

Add 9 to both sides

→ 18 = 9 k

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<em>The value of the constant k is 2</em>

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3 years ago
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Plate Tectonics

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I don't know if this was helpfull or not but I hope it was somewhat close to helpful? If it is not then please do not report this, I am sorry if this was the least bit helpful.

HAVE A NICE DAY! :)

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3 years ago
You have a perfectly circular apple pie with a radius of 15cm. You cut the pie into 12 approximately equal slices. What is the a
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