Given :
Three block of same mass name A , B and C .
Sides of block A , B and C is 3.0 cm , 5.0 cm and 10.0 cm .
To Find :
Which block has the higher density .
Solution :
We know , density
is given by :
......1 )
Here , V is volume .
Now , volume V for cube is given :
.......2 )
( Here , a is the side of cube )
Now ,form equation 1 we can see if mass remains constant then density decrease with increase in volume.
Therefore , cube with minimum side will have higher density , in this case it is 3 cm block .
Hence , this is the required solution .
<u>Answer:</u> The excess reactant for the given reaction is 
<u>Explanation:</u>
Limiting reagent is defined as the reagent which is present in less amount and it limits the formation of products.
Excess reagent is defined as the reagent which is present in large amount.
For the given chemical reaction:

We are given:
Moles of calcium nitrate = 3.4 mol
Moles of lithium phosphate = 2.4 mol
By stoichiometry of the reaction:
3 moles of calcium nitrate reacts with 2 moles of lithium phosphate
So, 3.4 moles of calcium nitrate will react with =
of lithium phosphate
As, the given amount of lithium phosphate is more than the required amount. So, it is considered as an excess reagent.
Thus, calcium nitrate is considered as the limiting reagent because it limits the formation of products.
Hence, the excess reactant for the given reaction is 
D) There is a large, apelike creature living in the Himalayas is a scientific statement. The other statements are basically opinions.
Hope this Helps!!
Answer:
There will be 525.2 grams of K3N produced
Explanation:
Step 1: Data given
Number of moles of potassium oxide ( K2O) = 6 moles
Magnesium nitride (Mg3N) = in excess
Molar mass of K3N = 131.3 g/mol
Step 2: The balanced equation
Mg3N2 + 3K2O → 3MgO + 2K3N
Step 3: Calculate moles of K3N
The limiting reactant is K2O.
For 1 mol Mg3N2 consumed, we need 3 moles of K2O to produce 3 moles of MgO and 2 moles of K3N
For 6 moles K2O we'll have 2/3 * 6 = 4 moles of K3N
Step 4: Calculate mass of K3N
Mass of K3N = moles K3N * molar mass K3N
Mass of K3N = 4 moles * 131.3 g/mol
Mass of K3N = 525.2 grams
There will be 525.2 grams of K3N produced