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slava [35]
3 years ago
6

An atom contains three protons, two neutrons, and one electron. What is the charge of the nucleus?

Chemistry
1 answer:
andreev551 [17]3 years ago
7 0

Answer:

A.3+

Explanation:

️️️️️️️️️️️️️️

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Which row probably contains the largest atoms on the periodic table?
svp [43]
The last row going across
7 0
3 years ago
Using the difference of electronegativities, determine whether each bond will be nonpolar covalent, polar covalent, or ionic. Sh
kati45 [8]

Answer:

so

Explanation:

7 0
3 years ago
What mass of oxygen is needed for the complete combustion of 4.60×10−3g of methane?
sp2606 [1]
First step in answering the question is to establish a balanced chemical reaction equation. More specifically, a combustion chemical equation. 

CH4 + 2O2 ---> CO2 + 2H20

Then using dimension analysis: 

4.60*10^{-3} g CH4 ( \frac{moleCH4}{16 g CH4}) * ( \frac{2mole O2}{mole CH4}) * ( \frac{32 g O2}{mole O2} ) =  0.0184 g O_{2}
7 0
3 years ago
An X-ray beam with λ = 157 pm incident on the surface of a crystal produced a maximum reflection at an angle of θ = 28.5 ∘. Assu
WARRIOR [948]

Answer:

The separation between layers of atoms in the crystal is 164.52 pm.

Explanation:

Formula used

n \lambda = 2d\sin \theta (Bragg's law)

Where :

n = an order of reflection (integer)

\lambda = wavelength of the beam incident X-ray

d = spacing between the layer

θ = incident angle ( angle between ray and scatter plane)

We have :

λ = 157 pm

θ = 28.5°

n = 1

d = ?

1\times 157 pm= 2d\sin (28.5^o) (Bragg's law)

d=\frac{1\times 157 pm}{2\times \sin (28.5^o)}=164.52 pm

The separation between layers of atoms in the crystal is 164.52 pm.

8 0
3 years ago
A 100.0 mL sample of 0.10 M Ca(OH)2 is titrated with 0.10 M HBr. Determine the pH of the solution after the addition of 300.0 mL
Vera_Pavlovna [14]

Answer : The correct option is, (C) 1.7

Explanation :

First we have to calculate the moles of Ca(OH)_2 and HBr.

\text{Moles of }Ca(OH)_2=\text{Concentration of }Ca(OH)_2\times \text{Volume of solution}=0.10M\times 0.1L=0.01mole

\text{Moles of }HBr=\text{Concentration of }HBr\times \text{Volume of solution}=0.10M\times 0.3L=0.03mole

The balanced chemical reaction will be:

Ca(OH)_2+2HBr\rightleftharpoons CaBr_2+2H_2O

0.01 mole of Ca(OH)_2 dissociate to give 0.01 mole of Ca^{2+} ion and 0.02 mole of OH^- ion

and

0.03 mole of HBr dissociate to give 0.03 mole of H^+ ion and 0.03 mole of Br^- ion

That means,

0.02 moles of OH^- ion  neutralize by 0.02 moles of H^+ ion.

The excess moles of H^+ ion = 0.03 - 0.02 = 0.01 mole

Total volume of solution = 100 + 300 = 400 ml = 0.4 L

Now we have to calculate the concentration of H^+ ion.

\text{Concentration of }H^+=\frac{\text{Moles of }H^+}{\text{Total volume}}

\text{Concentration of }H^+=\frac{0.01mole}{0.4L}=0.025M

Now we have to calculate the pH of the solution.

pH=-\log [H^+]

pH=-\log (0.025M)

pH=1.7

Therefore, the pH of the solution is, 1.7

5 0
3 years ago
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