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slava [35]
3 years ago
6

An atom contains three protons, two neutrons, and one electron. What is the charge of the nucleus?

Chemistry
1 answer:
andreev551 [17]3 years ago
7 0

Answer:

A.3+

Explanation:

️️️️️️️️️️️️️️

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if you had 16 tiles and each tile cost 80 cents how much change would you dmget back if you paid with 2 100 bills
olasank [31]

16 tiles x 0.80 = $12.80

If you have two 100 dollar bills, you have 200 dollars.

$200 - $12.80 = $187.20

5 0
3 years ago
Which functional group will cause a compound to have a boiling point greater than that predicted only by molar mass?
Mekhanik [1.2K]

Answer: Alcohol

Explanation:

5 0
2 years ago
Lithium reacts with chlorine to form a new substance.What other element will also with chlorine to form a new substance with sim
quester [9]

Answer:

Flourine

Explanation:

Chlorine is a member of the halogen family. Halogens are the elements that make up Group 17 (VIIA) of the periodic table, a chart that shows how elements are related to one another. They include fluorine, bromine, iodine, and astatine.

4 0
3 years ago
A student determines the molar mass of acetone, CH3COCH3, by the method used in this experiment. She found that the equilibrium
Alexandra [31]

Answer:

(a). 4°C, (b). 2.4M, (c). 11.1 g, (d). 89.01 g, (e). 139.2 g and (f). 58 g/mol.

Explanation:

Without mincing words let's dive straight into the solution to the question.

(a). The freezing point depression can be Determine by subtracting the value of the initial temperature from the final temperature. Therefore;

The freezing point depression = [ 1 - (-3)]° C = 4°C.

(b). The molality can be Determine by using the formula below;

Molality = the number of moles found in the solute/ solvent's weight(kg).

Molality = ( 11.1 / 58) × (1000)/ ( 90.4 - 11.1) = 2.4 M.

(c). The mass of acetone that was in the decanted solution = 11.1 g.

(d). The mass of water that was in the decanted solution = 89.01 g.

(e). 2.4 = x/ 58 × (1000/1000).

x = 2.4 × 58 = 139.2 g.

(f). The molar mass of acetone = (12) + (1 × 3) + 12 + 16 + 12 + (1 x 3) = 58 g/mol.

7 0
3 years ago
If 345.1 g of CO2 are placed in a vessel whose volume is 32.1 L at a temperature of 20.0oC, what will the pressure be? (R= 0.082
Finger [1]

Answer:

5.88atm

Explanation:

First, we obtain the number of mole of CO2 present in the vessel. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the question = 345.1g

Number of mole of CO2 =?

Number of mole = Mass/Molar Mass

Number of mole of CO2 = 345.1/44

= 7.84moles

Now we can easily calculate the pressure by doing the following:

Data obtained from the question include:

V (volume) = 32.1 L

T (temperature) = 20°C = 20 + 273 = 293K

R (gas constant) = 0.0821atm*L/mole*K

n (number of mole) = 7.84moles

P (pressure) =?

We will be making use of the ideal gas equation PV = nRT to calculate the pressure

PV = nRT

P = nRT/V

P = 7.84 x 0.0821 x 293/32.1

P = 5.88atm

Therefore, the pressure is 5.88atm

7 0
3 years ago
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