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3 years ago

What is the maximum number of double bonds that a hydrogen atom can form?

Physics

1 answer:

denis23 [38]3 years ago

8 0

Answer:

Explanation:

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas. The shared electron pair is common to the two atoms and holds them together.

In a double covalent bond each atom contributes two electrons to the bond, that is, two pairs of electrons are shared between the atoms that form the covalent bond.

The Hydrogen atom is made up of a proton and an electron, which is located in its outermost layer and allows the covalent bond to form. So <u><em>hydrogen cannot form a double bond </em></u>because it does not have the electrons necessary to form the bond. It needs two electrons in the valence shell or last shell and it only has a single electron.

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A pendulum on a grandfather clock

egoroff_w [7]

4.0 ilynits per second Alaskan es muy du facial in the oscillates 1.99

5 0

3 years ago

A residential subdivision encompasses 1100 acres with a housing density of four houses per acre. Assume that a high-value reside

aleksandrvk [35]

Answer:

(a). The average daily demand of this subdivision is 2444.44 gallon/min.

(b). The design-demand used to design the distribution system is 2444.44 gallon/min.

Explanation:

Given that,

Area = 1100 acres

Number of house in 1 acres = 4

$\text{Number of house in 1100 acres} = 4\times1100$

$\text{Number of house in 1100 acres} = 4400$

Per house water demand = 800 g/day/house

(a). We need to calculate the average daily demand of this subdivision

Using formula for average daily demand

$\text{average daily demand}=house\times\text{Per house water demand}$

$\text{average daily demand}=4400\times800\ gallon/day$

$\text{average daily demand}=3520000\ gallon/day$

$\text{average daily demand}=\dfrac{3520000}{24\times60}\ gallon/min$

$\text{average daily demand}=2444.44\ gallon/min$

The average daily demand of this subdivision is 2444.44 gallon/min.

(b). We need to calculate the design-demand used to design the distribution system

Using formula for the design-demand

$\text{design demand}=(Q_{max})daily\times\text{fire flow}$

$\text{design demand}=1.64\times2444.4\times1000$

$\text{design demand}=4008816\ gallon/m$

Hence, (a). The average daily demand of this subdivision is 2444.44 gallon/min.

(b). The design-demand used to design the distribution system is 2444.44 gallon/min.

8 0

3 years ago

Plz solve completely

tiny-mole [99]

Answer:

Explanation:

wouldnt it just be x=0 sorry if im

wrong

6 0

3 years ago

Convert the following dB to decimal a. -12 b. 3 c. 10 d. 0

stiks02 [169]

Answer:

for -12db

$\frac{V1}{V2}=0.251\\\\\frac{P1}{P2}=0.0631$

for 3db

$\frac{V1}{V2}=\sqrt{2}\\\\\frac{P1}{P2}=2$

for 10db

$\frac{V1}{V2}=3.16\\\\\frac{P1}{P2}=10$

for 0db

$\frac{V1}{V2}=1\\\\\frac{P1}{P2}=1$

Explanation:

The decibel is a logaritmic value given by:

$db=10*log(\frac{P1}{P2})=20*log(\frac{V1}{V2})$

we use 10 for power values and 20 for other values such voltages or currents.

$\frac{V1}{V2}=10^{\frac{db}{10}}\\\\\frac{P1}{P2}=10^{\frac{db}{20}}$

for -12db

$\frac{V1}{V2}=10^{\frac{-12}{10}}=0.251\\\\\frac{P1}{P2}=10^{\frac{-12}{20}}=0.0631$

for 3db

$\frac{V1}{V2}=10^{\frac{3}{10}}=\sqrt{2}\\\\\frac{P1}{P2}=10^{\frac{3}{20}}=2$

for 10db

$\frac{V1}{V2}=10^{\frac{10}{10}}=3.16\\\\\frac{P1}{P2}=10^{\frac{10}{20}}=10$

for 0db

$\frac{V1}{V2}=1\\\\\frac{P1}{P2}=1$

4 0

3 years ago

madam [21]

Answer:

p = mv

Explanation:

The momentum of a body is defined as the product of its mass and velocity. Its physical symbol is 'p'.
The formula for momentum is given by

p = mv

Where,

m - the mass of the body in kg

v - velocity of the body in m/s

Therefore, the unit of momentum is expressed as the kg m/s
The momentum of a body is always associated with its motion. It is a vector quantity and it is directed in the direction of the velocity vector.
If a body is at rest, the momentum associated with the body is zero.
The momentum plays a significant role in the kinematics of the body. As similar to the energy conservation law, the total momentum of the body is conserved.

6 0

3 years ago