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3 years ago

Chemical energy is a form of _____ energy.

Chemistry

1 answer:

inn [45]3 years ago

6 0

Answer: Option (d) is the correct answer

Explanation:

The energy present within the bonds of the atoms of a compound or molecule is known as chemical energy.

As this energy is present at a position that is, within the bonds hence it is a potential energy. So, whenever there occurs a chemical reaction the stored chemical energy is released.

As potential energy is the energy possessed because of position of a substance. And, kinetic energy is the energy present due to the motion of an object.

Therefore, we can conclude that chemical energy is a form of potential energy.

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Ilya [14]

Answer:

option b is correct

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3 years ago

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What gender are the blues from angry birds

trapecia [35]

they are male

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3 years ago

When a 3.25 g sample of solid sodium hydroxide was dissolved in a calorimeter in 100.0 g of water, the temperature rose from 23.

sertanlavr [38]

Answer : The enthalpy change for the solution is 42.8 kJ/mol

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $15.8J/^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m$ = mass of water = 100.0 g

$\Delta T$ = change in temperature = $T_2-T_1=(32.0-23.9)=8.1^oC$

Now put all the given values in the above formula, we get:

$q=[(15.8J/^oC\times 8.1^oC)+(100.0g\times 4.18J/g^oC\times 8.1^oC)]$

$q=3513.8J=3.5138kJ$ (1 kJ = 1000 J)

Now we have to calculate the enthalpy change for the solution.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 3.5138 kJ

m = mass of NaOH = 3.25 g

Molar mass of NaOH = 40 g/mole

$\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{3.25g}{40g/mole}=0.0812mole$

Now,

$\Delta H=\frac{3.5138kJ}{0.0821mole}=42.8kJ/mol$

Therefore, the enthalpy change for the solution is 42.8 kJ/mol

4 0

3 years ago

A 100g piece of iron at 150oC is emersed in 268.5 g of water at 20oC. the temperature of both iron and water became 25oC. If the

borishaifa [10]

Answer:

cW = 4.2J/g.k

Explanation:

Heat gained = Heat lost

iron(mc∆€) = water(mc∆€)

mi= 100g

ci = 0.449

∆€i= 150-25 = 125

...

mw= 268.5g

cw = ?

∆€w=25-20 = 5

...

100×0.449×125= 268.5×cw×5

5612.5= 1342.5cw

cw = 5612.5/1342.5

cw= 4.18 ~ 4.2J/g.K

4 0

2 years ago

When 0.873 grams of a protein were dissolved in 48.6 mL of solution at 15.6 degrees C, the osmotic pressure was found to be 0.06

Stels [109]

Answer:

697 g / mol

Explanation:

The osmotic pressure of a protein ( non electrolyte ) is given by:

π V= nRT where V is the volume, n is the number of moles, R is the gas constant ( 0.08206 L·atm/Kmol ), and T is the temperature (K).

n= mass/ MW protein ⇒ MW protein = mass / n

Thus,

π V = ( mass/ MW ) RT

MW = mass x R xT/ ( π V )

mass = 0.873 g

R = 0.08206 L·atm/K·mol

T = ( 15.6 + 273 ) K= 288.6 K

π = 0.061 atm

V = 48.6 mL = 48.6 mL x ( 1 L/ 1000 mL ) = 0.0486 L

We just need to plug our values into the aqbove equation for MW:

MW = 0.873 g x 0.08205 L· atm /K·mol x 288.6 K / ( 0.061 atm x0.0486 L )

= 697 g/mol

6 0

3 years ago