Answer:
ω = 2.1 rad/sec
Explanation:
- As the rock is moving along with the merry-go-round, in a circular trajectory, there must be an external force, keeping it on track.
- This force, that changes the direction of the rock but not its speed, is the centripetal force, and aims always towards the center of the circle.
- Now, we need to ask ourselves: what supplies this force?
- In this case, the only force acting on the rock that could do it, is the friction force, more precisely, the static friction force.
- We know that this force can be expressed as follows:

where μs = coefficient of static friction between the rock and the merry-
go-round surface = 0.7, and Fn = normal force.
- In this case, as the surface is horizontal, and the rock is not accelerated in the vertical direction, this force in magnitude must be equal to the weight of the rock, as follows:
- Fn = m*g (2)
- This static friction force is just the same as the centripetal force.
- The centripetal force depends on the square of the angular velocity and the radius of the trajectory, as follows:

- Since (1) is equal to (3), replacing (2) in (1) and solving for ω, we get:

- This is the minimum angular velocity that would cause the rock to begin sliding off, due to that if it is larger than this value , the centripetal force will be larger that the static friction force, which will become a kinetic friction force, causing the rock to slide off.
Answer:
The rock cycle is the process by which rocks of one kind change into rocks of another kind. ... Metamorphic rock is igneous or sedimentary rock that has been heated and squeezed. It can erode into sediment or melt into magma.
Explanation:
The two possible distances that you might infer your friends swam while the lights were out are 25 m and 75 m.
Answer:
Explanation:
So you have to measure the distance covered by your friend in a time gap of 86 s. And the average velocity is given as 0.29 m/s.
Then as per the mathematical calculation of velocity, distance can be measured as the product of velocity with time interval.
Distance = Velocity × Time Interval
Distance = 0.29 m/s×86 s = 24.94 m.
So based on this calculation, one of the possible distance inferred by you will be 24.94 m.
Another possible distance can be guessed from the statements provided. So if the length of pool is 50 m, then covering halfway in opposite direction to his starting direction means completion of one full length i.e., 50 m and then halfway of that 50 m which is 25m, so totally 50 +25 = 75 m.
So in other way, we can assume that your friend has covered 75 m distance during the light out.
Thus, the two possible distances that you might infer your friends swam while the lights were out are 25 m and 75 m.