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barxatty [35]
3 years ago
13

Elements classified as metals, nonmetals, and metalloids. Can you use the periodic table to locate these groups of elements? Wha

t do these locations reveal about these groups of elements
Chemistry
1 answer:
Lemur [1.5K]3 years ago
3 0

Based on the electronic configuration the elements are classified as metals, non metals and metalloids.

<u>Explanation:</u>

Periodic table consists of three major parts.

The left side consists of metals and the right side consists of non-metals and here Hydrogen element is the exception and in between those two regions we have metalloids, which has the dual character of both metals and non metals.

These elements can be grouped by means of its chemical properties and also  due to its outermost electronic configuration.

If the valence shell electrons are same they are categorized under same group.

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Calculate the final concentration of each of the following:
kkurt [141]

Answer:

1. 2 M

2. 2 M

Explanation:

1. Determination of the final concentration.

Initial Volume (V₁) = 2 L

Initial concentration (C₁) = 6 M

Final volume (V₂) = 6 L

Final concentration (C₂) =?

The final concentration can be obtained as follow:

C₁V₁ = C₂V₂

6 × 2 = C₂ × 6

12 = C₂ × 6

Divide both side by 6

C₂ = 12 / 6

C₂ = 2 M

Therefore, the final concentration of the solution is 2 M

2. Determination of the final concentration.

Initial Volume (V₁) = 0.5 L

Initial concentration (C₁) = 12 M

Final volume (V₂) = 3 L

Final concentration (C₂) =?

The final concentration can be obtained as follow:

C₁V₁ = C₂V₂

12 × 0.5 = C₂ × 3

6 = C₂ × 3

Divide both side by 3

C₂ = 6 / 3

C₂ = 2 M

Therefore, the final concentration of the solution is 2 M

7 0
2 years ago
What volume of 12 M NaOH and 2 M NaOH should be mixed to get 2 litres of 9 M NaOH solution?
Sergio [31]
8/5lit.. of 12M NaOH
2/5lit.. of 2M NaOH
7 0
3 years ago
Which of the following is not a part of every scientific investigation?
Dmitry_Shevchenko [17]

Answer:

the correct answer is Group of answer choices

6 0
3 years ago
Riley is doing an experiment working with friction. He wants to find two ways to modify an object that could increase or decreas
Shtirlitz [24]
Riley can either change the surface area of the object or can change the slipperiness of the material.
5 0
2 years ago
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A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical
Katarina [22]

Answer:

empirical formula: H_2SO_4

2 g H

32.7 g S

65.3 g O

Explanation:

Like the problem said, the first thing we can do is calculate the mass of each of the 3 elements in a 100-gram sample:

- 2.00% * 100g = 2 g H

- 32.7% * 100g = 32.7 g S

- 65.3% * 100g = 65.3 g O

Now we need to find the empirical formula from these. To do so, convert all of those masses into moles by using the molar mass for each element:

- the molar mass of H is 1.01 g/mol

- the molar mass of S is 32.06 g/mol

- the molar mass of O is 16 g/mol

2 g H ÷ 1.01 g/mol = 1.98 mol H

32.7 g S ÷ 32.06 g/mol = 1.02 mol S

65.3 g O ÷ 16 g/mol = 4.08 mol O

Our ratio of H : S : O is now:

1.98 mol : 1.02 mol : 4.08 mol

Divide them all by the smallest number, which is 1.02:

1.98/1.02  :  1.02/1.02  :  4.08/1.02

1.94 : 1 : 4

1.94 ≈ 2

So:

2 : 1 : 4

Thus, the empirical formula is: H_2SO_4.

7 0
3 years ago
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