Answer:
The magnitude of the force required to move the electron through the given field is 2.203 N
Explanation:
Given;
The field strength of the electron, E = 1.375 x 10¹⁹ N/C
charge of electron, q = 1.602 x 10⁻¹⁹ C
The magnitude of the force required to move the electron through the given field is calculated as follows;
F = Eq
F = (1.375 x 10¹⁹ N/C) (1.602 x 10⁻¹⁹ C)
F = 2.203 N
Therefore, the magnitude of the force required to move the electron through the given field is 2.203 N
(a) The velocity ratio of the screw is 1570.8.
(b) The mechanical advantage of the screw is 785.39.
<h3>
Velocity ratio of the screw</h3>
The velocity ratio of the screw is calculated as follows;
V.R = 2πr/P
where;
- P is the pitch = 1/10 cm = 0.1 cm = 0.001 m
- r is radius = 25 cm = 0.25 m
V.R = (2π x 0.25)/(0.001)
V.R = 1570.8
<h3>Mechanical advantage of the screw</h3>
E = MA/VR x 100%
0.5 = MA/1570.8
MA = 785.39
Learn more about mechanical advantage here: brainly.com/question/18345299
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Atomic Number
or
Number of Protons
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