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marta [7]
2 years ago
12

Two identical cars, each traveling at the same velocity, and having the same mass come to a stop

Physics
1 answer:
olya-2409 [2.1K]2 years ago
4 0

Answer:

The second option - same change in momentum, different force

Explanation:

They experience the same change in momentum, but the force on car A is greater.

p=m*v

Impulse, or change in p=F*t

We know the cars have the same change in momentum, because they both go from the same initial momentum (p=mv), to zero momentum. Therefore, both experience the same change in momentum. Since the time is different, but the change in momentum is the same, the force has to be different.

For example: if both cars had 200 kg*m/s of momentum at the start, and 0 at rest, the impulse is 200 kg*m/s

So,

p(a)=    200=F(0.3)

p(b)=    200=F(5)

Which force has to be greater to make the equations true? The force for Car A, of course!

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A 19 g bullet is fired into the bob of a ballistic pendulum of mass 1.3 kg. When the bob is at its maximum height, the strings m
katovenus [111]

Answer:

217.43298 m/s

Explanation:

m_1 = Mass of bullet = 19 g

m_2 = Mass of bob = 1.3 kg

L = Length of pendulum = 2.3 m

\theta = Angle of deflection = 60°

u = Velocity of bullet

Combined velocity of bullet and bob is given by

v^2-u^2=2as\\\Rightarrow v=\sqrt{2aL(1-cos\theta)+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times (1-cos60)+0^2}\\\Rightarrow v=3.13209\ m/s

As the momentum is conserved

m_1u=(m_1+m_2)v\\\Rightarrow u=\frac{(m_1+m_2)v}{m_1}\\\Rightarrow v=\frac{(0.019+1.3)\times 3.13209}{0.019}\\\Rightarrow v=217.43298\ m/s

The speed of the bullet is 217.43298 m/s

5 0
3 years ago
A vocalist with a bass voice can sing as low as 92 Hz.
Inessa05 [86]

Answer:

  • 3.26 x 10 to the power of 6

Explanation:

c = lambda × frequency

5 0
3 years ago
The period of rotation of Mars is 1 day and 37 minutes. Determine its frequency of rotation in Hertz.
Sholpan [36]

The frequency of rotation of Mars is 0.0000113 Hertz.

<u>Given the following data:</u>

  • Period = 1 day and 37 minutes.

To find the frequency of rotation in Hertz:

First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.

<u>Conversion:</u>

1 day = 24 hours

24 hours to minutes = 60 × 24 = 1440 minutes

1440 + 37 = 1477 \; minutes

1 minute = 60 seconds

1477 minute = X seconds

Cross-multiplying, we have:

X = 60 × 1477

X = 88620 seconds

Now, we can find the frequency of rotation of Mars by using the formula:

Frequency = \frac{1}{Period}\\\\Frequency = \frac{1}{88620}

<em>Frequency </em><em>of rotation</em> = <em>0.0000113 Hertz</em>

Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.

Read more: brainly.com/question/14708169

8 0
2 years ago
Afootball of mass 550g is at rest on the ground the football is kicked with a force of 108 newton the footballers boot is in con
d1i1m1o1n [39]

If "0.3 minute" is correct, then it's 9,543,272 Joules.

If it's supposed to say "0.3 SECOND", then the KE is 2,651 Joules.

6 0
3 years ago
PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer these correctly!!!! (40pts)
denpristay [2]

Answer:

False, true

Explanation:

3 0
3 years ago
Read 2 more answers
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