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m_a_m_a [10]
2 years ago
7

Problem 24.3 The assembly is made from a steel hemisphere, rho st = 7. 80 Mg/m3 , and an aluminum cylinder, rho al = 2. 70 Mg/m3

. If the height of the cylinder is h = 180 mm, determine the location z of the mass center of the assembly.
Physics
1 answer:
AlladinOne [14]2 years ago
3 0

Answer:

0.12 m    

Explanation:

The mass of the steel hemisphere is:

m_h=\rho_s\times \frac{2}{3}\pi r^2\\m_h = 7.8\times 10^3 \times \frac{2}{3}\pi (0.16)^2\\m_h=66.9 kg

Mass of the aluminium cylinder is:

m_c=\rho_a\times \pi r^2 h\\m_c=2.7\times 10^3 \times \pi (0.08)^2(0.18) \\m_c =9.7 kg

mass center of steel hemisphere from the bottom:

z_1=r-3r/8\\z_1=0.16-(3\times 0.16/8) =0.1 m

mass center of aluminium cylinder from the bottom:

z_2=r+h/2 \\z_2=0.16+0.18/2=0.25 m

center of mass is

Z=\frac{m_hz_1+z_2m_c}{m_s+m_c}\\Z=\frac{66.9\times 0.1+9.76\times 0.25}{66.9+9.76} = 0.12 m

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Answer:

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3 years ago
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Answer:

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density, ρ = 0.888 g/cm³ = 0.888 X 10³ kg/m³

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mass of the oil drop = density, ρ  X volume of the oil drop

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mass of the oil drop = 0.888 X 10³ (kg/m³) X 10.584 X 10⁻¹⁸ (m³)

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