Answer:

Explanation:
We are given that
Diameter of wire=d=4.12 mm
Radius of wire=r

Current=I=8 A
Drift velocity=
We have to find the density of free electrons in the metal
We know that
Density of electron=
Using the formula
Density of free electrons=
By using Area of wire=

Density of free electrons=
Answer:
Loudness of the second sound is more than the first one.
Explanation:
There are two sounds, the second sound is identical to first but the loudness of second is more than the first one.
As the frequency is same so the itch is same for both the sounds.
As the loudness depends on the amplitude of the sound so the loudness of the second sound is more than the first sound.
10.3
Explanation:
Step 1:
The pressure exerted by any liquid column of height, h density d is given by the formula P = h * d * g
Step 2:
It is given that one atmosphere pressure pushes up 76.0 cm of mercury, we need to calculate the level of water that will be pushed by the same pressure.
Step 3:
Since the pressure pushing up mercury and water is the same
*
* g =
*
* g
=
= (13.6 g/cm * 76 cm)/1 g/cm = 1033.6 cm
Step 4:
Now we need to express the answer in meters.
1 m = 100 cm.
1033.6 cm = 10.336 m
This can be rounded off to 10.3 m