3 years ago

Calculate the pH of 0.030 M NH4CI

Chemistry

1 answer:

Sati [7]3 years ago

6 0

Answer:

1.52

Explanation:

-log(.030)

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Write the net ionic equation for the reaction of aqueous solutions of ammonium chloride and iron(III) hydroxide.

vagabundo [1.1K]

Answer:

$Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)$

Explanation:

Hello.

In this case, for the reaction between aqueous solutions of ammonium chloride and iron (III) hydroxide, we have the following complete molecular reaction:

$3NH_4Cl(aq)+Fe(OH)_3(s)\rightarrow 3NH_4OH+FeCl_3$

And the full ionic equation, taking into account that the iron (III) hydroxide cannot be dissolved as it is insoluble in water:

$3NH_4^+(aq)+3Cl^-(aq)+Fe(OH)_3(s)\rightarrow 3NH_4^+(aq)+3OH^-(aq)+Fe^{3+}(aq)+3Cl^-(aq)$

Finally, the net ionic equation, considering that spectator ions are NH₄⁺, Cl⁻ as they are both the left and right side, therefore, the net ionic equation is:

$Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)$

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The following equation represents the type of reaction called

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If the ph of hc3h5o2 is 4.2 and the ka 1.34x10^-5, what is the equilibrium concentration

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CH₃CH₂COOH + H₂O ↔ CH₃CH₂COO⁻ + H₃O⁺

pH = 0.5 pKa + 0.5 pCa
0.5 pCa = pH - 0.5 pKa
= 4.2 - (0.5 * (-log 1.34 x 10⁻⁵)) = 1.76
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