Explanation:
Here I send you all the 3 elements that you are asking for.
Notice that first on the left you will find lewis structure, then condensed and finally chemical formula of each of the compound you enlisted.
I don’t know what exactly is but see at the picture.
<u>Answer:</u> The chemical formula of Iron (III) sulfate is
<u>Explanation:</u>
Iron is the 26th element of periodic table having electronic configuration of .
To form ion, this element will loose 3 electrons.
Sulfate ion is a polyatomic ion having chemical formula of
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
So, the chemical formula for Iron (III) sulfate is
According to boiling point elevation equation:
Δ T = i Kb m
when ΔT (change in boiling point) = 7.10 C°
and i (van't Hoff factor)= 1
and Kb = 0.520
so, by substitution:
7.10 = 1*0.520 *m
m = 7.1 / 0.52 = 13.65 m
Answer: Option (D) is the correct answer.
Explanation:
Atomic number of chlorine is 17 and its electronic distribution is 2, 8, 7.
So, in order to attain stability it tends to gain one electron from a donor atom. Therefore, a chlorine ion is formed as .
As it gains only one electron that is why, -1 charge occurs.
Whereas Ar is a noble gas with atomic number 18. As it has completely filled octet so it will be unreactive in nature as it is already stable.
Similarly, He is also a noble gas so it is unreactive in nature.
Atomic number of boron (B) is 5 with electronic distribution 2, 3. So, in order to attain stability it needs to lose 3 electrons.
Thus, we can conclude that Cl is the atom which tends to gain 1 valence electron from another atom in order to become stable.