Answer:
3AgNO₃ (aq) + Na₃PO₄(aq) → Ag₃PO₄(s) ↓ + 3NaNO₃(aq)
Explanation:
The reaction is:
3AgNO₃ (aq) + Na₃PO₄(aq) → Ag₃PO₄(s) ↓ + 3NaNO₃(aq)
3 moles of silver nitrate and 1 mol of sodium phosphate, react in order to produce 1 mol of solid silver phosphate 3 moles of sodium nitrate
3Ag⁺(aq) + PO₄³⁻ (aq) → Ag₃PO₄(s) ↓
Explanation:
Evaluate the results, letter B
2Na + 2H2O ----> H2 + 2Na(OH)
48.7/23 = 2.12 moles sodium
2.12/2 x 24 = 25.44dm^3 hydrogen = 1.06 moles
1.06 X 6.02x10^23 = 1.204x10^24 molecules of hydrogen