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kobusy [5.1K]
3 years ago
7

Helpp please ASAP...​

Physics
1 answer:
Korolek [52]3 years ago
5 0

Answer:

I believe it to be option A

Explanation:

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A lion has a mass of 45 kg. Answer the following questions about it, using correct units. a. The lion runs at a speed of 14.2 m/
Eva8 [605]
A) The kinetic energy of an object is given by:
K= \frac{1}{2}mv^2
where m is the mass of the object, and v its speed. For the lion in our problem, m=45 kg and v=14.2 m/s, so its kinetic energy is
K= \frac{1}{2}mv^2= \frac{1}{2}(45 kg)(14.2 m/s)^2=4537 J

b) the increase in gravitational potential energy of the lion is given by:
\Delta U = mg \Delta h
where g is the gravitational acceleration, and \Delta h is the increase in altitude of the lion. In this problem, \Delta h=28 m, so the increase in gravitational potential energy is
\Delta U=mg \Delta h=(45 kg)(9.81 m/s^2)(28 m)=12361 J

c) When the fox reaches the top of the tree, its gravitational potential energy is
U=mgh=(1.8 kg)(9.81 m/s^2)(3.8 m)=67 J
As it jumps, its kinetic energy is
K= \frac{1}{2}mv^2= \frac{1}{2}(1.8 kg)(8.1 m/s)^2=59 J
So the total mechanical energy of the fox as it jumps is
E=U+K=67 J + 59 J =126 J
6 0
3 years ago
In a standard tensile test, a steel rod of 7 8-in. diameter is subjected to a tension force of 17 kips. Knowing that ν = 0.30 an
natali 33 [55]

Answer:

(a) Elongation of the rod==5.61×10⁻⁹m

(b) Change in diameter=1.640×10⁻⁸m

Explanation:

Given data

Diameter d=78 in=1.9812 m

Cross Area is:

A=(\pi /4)d^{2} \\A=(\pi /4)(1.9812m)^{2}\\A=3.08m^{2}

Applied Load P=17 KN=17×10³N

E=29 × 106 psi=1.99947961×10¹¹Pa

Stress and Strain in x direction

Stress in x direction

σ=P/A

=\frac{17*10^{3}N }{3.08m^{2} }\\ =5517.25Pa

σ=5517.25 Pa

Strain in x direction

ε=σ/E

=\frac{5517.25}{1.99947961*10^{11} } \\=2.76*10^{-8}

ε=2.76×10⁻⁸

Part (a)

Elongation of the rod=Lε

=(0.2032)(2.76×10⁻⁸)

Elongation of the rod==5.61×10⁻⁹m

Part(b) Change in diameter

Strain in y direction

ε₁= -vε

ε₁= -(0.30)(2.76×10⁻⁸)

ε₁=-8.28×10⁻⁹

Change in diameter=d×ε₁

Change in diameter=(1.9812m)×(-8.28×10⁻⁹)

Change in diameter=1.640×10⁻⁸m

4 0
3 years ago
How many mL are in a cubic centimeter?
Furkat [3]
None of the above. 1 mL= 1 cubic centimeter
mm is the smallest.
4 0
3 years ago
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If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed
beks73 [17]

Answer:

v = 5.9 x 10⁷ m/s

Explanation:

The kinetic energy of the electron in terms of potential difference is given as:

K.E = eV--------------- equation (1)

where,

e = charge on electron = 1.6 x 10⁻¹⁹ C

V = Potential Difference = 9.9 KV = 9900 Volts

The kinetic energy in general is given as:

K.E = \frac{1}{2}mv^{2}\\--------- equation (2)

where,

m = mass of electron = 9.1 x 10⁻³¹ kg

v = speed of electron = ?

Therefore, comparing equation (1) and equation (2), we get:

\\\frac{1}{2}mv^{2} = eV\\\\\frac{1}{2}(9.1\ x\ 10^{-31}\ kg)v^{2} = (1.6\ x\ 10^{-19}\ C)(9900\ volts)\\\\v = \sqrt{34.81\ x\ 10^{14}} \\

<u>v = 5.9 x 10⁷ m/s</u>

8 0
3 years ago
Which statement best summarizes the central idea of “Applications of Newton’s Laws”?
Shkiper50 [21]

 

Newton's three forces, normal, tension and friction, are present in a surprising number of physical situations

Newton's Laws, that describe the relationship between an obejct and the forces acting upon it, apply in almost every physical situation, from quantum mechanics to electricity.

The correct answer is:

Newton’s laws can explain the forces that occur between objects every day


3 0
3 years ago
Read 2 more answers
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