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Whitepunk [10]
3 years ago
8

A placebo is a substance that is unlikely to affect the dependent variable.

Chemistry
2 answers:
Sergio039 [100]3 years ago
6 0

Answer : Option a) True.

Explanation : A placebo is a substance that is unlikely to affect the dependent variable. True as in a clinical trial for any change in the placebo arm is known as the placebo response, and the difference between this placebo response and the result of no treatment is called as the placebo effect. Therefore, a placebo may be given to any person in a clinical context in order to deceive that recipient into thinking that it is an part of active treatment. It actually resembles a drug but is not an actual active drug, so, it is clear that it will not affect dependent variable.

SpyIntel [72]3 years ago
6 0
True. A placebo is a substance used to ensure that the independent variable is what is affecting the dependent variable. Usually used in drug trials
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The normal freezing point of a certain liquid
slavikrds [6]

Answer : The molal freezing point depression constant of liquid X is, 4.12^oC/m

Explanation :  Given,

Mass of urea (solute) = 5.90 g

Mass of liquid X (solvent) = 450 g  = 0.450 kg

Molar mass of urea = 60 g/mole

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}}{\text{Molar mass of urea}\times \text{Mass of liquid X Kg}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -0.5^oC

\Delta T^o = freezing point of liquid X = 0.4^oC

i = Van't Hoff factor = 1 (for non-electrolyte)

K_f = Molal-freezing-point-depression constant = ?

m = molality

Now put all the given values in this formula, we get

0.4^oC-(-0.5^oC)=1\times K_f\times \frac{5.90g}{60g/mol\times 0.450kg}

K_f=4.12^oC/m

Therefore, the molal freezing point depression constant of liquid X is, 4.12^oC/m

3 0
3 years ago
Which best describes the purpose of this blog post?
Yakvenalex [24]

Answer:

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6 0
4 years ago
A tow truck does 10,000 J of work in 5 seconds. Calculate the power.
chubhunter [2.5K]

Answer:

power is work/time so 10,000j/5s=2000J/s

5 0
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Which of the following is the correct formula for sulfuric acld?
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Explanation:

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GrogVix [38]

Answer:

The correct answer is C. element

Explanation:

The sample cannot be an element because an element - or <em>elemental substance</em> - cannot be decomposed into simpler substances. Thus, it cannot be composed by differents types of atoms. For example, an element is carbon (C).

As the sample contains <u>three types of atoms</u>, it can be a compound, a molecule or a mixture, because they can be composed by different types of atoms - of different chemical elements. For example, the sample could contain the element carbon (C) combined with other elements, for example oxygen (O) or hydrogen (H), amoing others.

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3 years ago
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