Answer:
<em>Hewo Otaku Kun Here! (UwU)</em>
Explanation:
1. A rock sitting at the edge of a cliff has potential energy. If the rock falls, the potential energy will be converted to kinetic energy.
2. Tree branches high up in a tree have potential energy because they can fall to the ground.
3. A stick of dynamite has chemical potential energy that would be released when the activation energy from the fuse comes into contact with the chemicals.
4. The food we eat has chemical potential energy because as our body digests it, it provides us with energy for basic metabolism.
5. A stretched spring in a pinball machine has elastic potential energy and can move the steel ball when released.
6. When a crane swings a wrecking ball up to a certain height, it gains more potential energy and has the ability to crash through buildings.
7. A set of double "A" batteries in a remote control car possess chemical potential energy which can supply electricity to run the car.
<em>happy to help!</em>
<em>from: Otaku Kun ^^</em>
Answer:
F = 1.6*10⁴ N
Explanation:
Given distance x = 0.15m, mass m = 1200kg, velocity v = 2m/s.
Unknown: force F
Force is given by Newton's law:
(1)
The average force to stop an object from a velocity will be the same force necessary to accelerate an object from rest to the same velocity.
The distance for an object starting from rest for a constant acceleration is given by:
(2)
The velocity for an object starting from rest for a constant acceleration:
(3)
Using equation 2 and 3 to eliminate time t:
(4)
Solving equation 4 for the acceleration a:
(5)
Using equation1 to solve for the force F:
(6)
Answer:
Explanation:
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
= Mass of sphere = 2000 kg
= Mass of other sphere = 2.1 kg
r = Distance between spheres
Force of gravity is given by
The gravitational force is
The gravitational force is
Answer:
b) Distance covered before stopping.
Explanation:
If you want to find the distance d required to come to a stop starting at some initial speed v, with braking acceleration a, use the kinematic relation
vf2 - vi2 = 2ad
vi = initial speed at the moment braking begins = v
vf = final speed = 0 (comes to a full stop)
-v2 = 2ad
d = -v2/(2a)