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Aleksandr [31]
2 years ago
6

Necesito que me ayuden a completar mi tabla con esa activada de ppm y eso se me complica mucho​

Chemistry
1 answer:
pashok25 [27]2 years ago
4 0
Solo multiplico y ya
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ASAP MULTIPLE CHOICE WILL MARK BRAINLIEST
QveST [7]
Average atomic mass = .374 ( 184.953 amu ) + .626 ( 186.958 amu ) =
186.207 amu
Hope this helps x
would love to have brainliest if it is right! :)
6 0
3 years ago
If an object has two forces acting on it how can the next force equal 0
Flura [38]

If the forces are equal and in opposite directions, the net force will equal zero.

Consider a tug-of-war team. If they are pulling with equal forces against each other, the red cloth on the rope will not move.

<em>F = ma </em>

The cloth is not moving, so <em>a = </em>0 and the net force <em>F = </em>0.

6 0
3 years ago
Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)
Brums [2.3K]

Answer:1) Volume of AgNO_3 required is 55.98 mL.

2) 0.62577 grams of Ag_3PO_4 is produced.

Explanation:

3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)

1) Molarity of AgNO_3,M_1=0.225 M

Volume of AgNO_3.V_1=?

Molarity of Na_3PO_4,M_2=0.135 M

Volume of Na_3PO_4,V_2=31.1 mL=0.0311 L

Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}

\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles

According to reaction, 1 mole of Na_3PO_4 reacts with 3 mole of AgNO_3, then, 0.0041985 moles of Na_3PO_4 will react with:

\frac{3}{1}\times 0.0041985 moles of AgNO_3 that is 0.0125955 moles.

M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}

V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL

Volume of AgNO_3 required is 55.98 mL.

2)

Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}

Number of moles of AgNO_3=0.195\times 0.023 L=0.004485 moles

According to reaction, 3 moles of AgNO_3 gives 1 mole of Ag_3PO_4, then 0.004485 moles of AgNO_3 will give:\frac{1}{3}\times 0.004485 moles of Ag_3PO_4 that is 0.001495 moles.

Mass of Ag_3PO_4 =

Moles of Ag_3PO_4 × Molar Mass of Ag_3PO_4

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of Ag_3PO_4 is produced.

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3 years ago
How do cells respond to contact with other cells?
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It depends on the function and activity of both cells. Most normal cells crease division if they came into contact with other cells however the immune system interact directly with pathogens or foreign organisms to destroy them.
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Which type of molecule is shown below?
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The answer is A. It is an alkyn. There is a triple bond
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