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xxMikexx [17]
2 years ago
9

A 33.6 mL solution of KCl has a mass of 27.29 g. After evaporating to dryness, the dry salt residues has a mass of 6.31 g. Calcu

late the following: a. %m/m b. Molarity (M)
Chemistry
1 answer:
bixtya [17]2 years ago
4 0

For  the molarity and the  percentage of the mass of kcl are mathematically given as

%m/m = 23.1%, molarity  = 3.38M

<h3>What is the molarity?</h3>

Generally, the equation for the  percentage of the mass of kcl is mathematically given as

(mass of kcl/mass of solution)x 100

therefore

%m/m = (6.31/27.29)x100

%m/m = 23.1%

The molarity

(no of mol/ vol of sol)

molarity  = 0.0846mol/0.0250 L

molarity  = 3.38M

In conclusion, the molarity is given as

molarity  = 3.38M

Read more about Molarity

brainly.com/question/9149034

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The organic compound di‑n‑butyl phthalate, C 16 H 22 O 4 ( l ) , C16H22O4(l), is sometimes used as a low‑density ( 1.046 g ⋅ mL
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Answer:

36.63 Torr

Explanation:

You need to use two expressions, one for pressure and the other with the relation of density and height of the column.

For the pressure:

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h is height.

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The second expression put a relation between the densities and height of the column so:

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let 1 be the phthalate, and 2 the mercury.

Let's calculate first the relation of density:

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replacing:

h2 = 459 / 12.53

h2 = 36.63 mm

1 mmHg is 1 torr, therefore the pressure of the gas in Torr would be 36.63 Torr

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