The momentum of the second object is 125 kg m/s
Explanation:
The momentum of an object is given by
where
m is the mass of the object
v is its velocity
For the object in this problem,
And its mass is m and its velocity is v.
The second object has a mass of and same velocity v, so its momentum is
So, the second object has a momentum that is half of the momentum of the first object, therefore it is:
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Answer:
Average force, F = 562.5 N
Explanation:
Mass of the golf ball, m = 0.045 kg
Initially, it is at rest, u = 0
Final speed of the ball, v = 25 m/s
The club and the ball are in contact for,
We need to find the average force acting on the ball. It can be calculated using the formula as :
F = 562.5 N
So, the average force acting on the ball is 562.5 N. Hence, this is the required solution.
Answer:
Final Speed of Dwayne 'The Rock' Johnson = 15.812 m/s
Explanation:
Let's start out with finding the force acting downwards because of the mass of 'The Rock':
Dwayne 'The Rock' Johnson: 118kg x 9.81m/s = 1157.58 N
Now the problem also states that the kinetic friction of the desk in this problem is 370 N
Since the pulley is smooth, the weight of Dwayne Johnson being transferred fully, and pulls the desk with a force of 1157.58 N. The frictional force of the desk is resisting this motion by a force of 370 N. Subtracting both forces we get the resultant force on the desk to be: 1157.58 - 370 = 787.58 N
Now lets use F = ma to calculate for the acceleration of the desk:
787.58 = 63 x acceleration
acceleration = 12.501 m/s
Finally, we can use the motion equation:
here u = 0 m/s (since initial speed of the desk is 0)
a = 12.501 m/s
and s = 10 m
Solving this we get:
Since the desk and Mr. Dwayne Johnson are connected by a taught rope, they are travelling at the same speed. Thus, Dwayne also travels at 15.812 m/s when the desk reaches the window.