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Viefleur [7K]
3 years ago
5

Fifteen identical particles have various speeds: one has a speed of 2.00 m/s, two have speeds of 3.00 m/s, three have speeds 5.0

0 m/s, four have speeds of 7.00 m/s, three have speeds of 9.00 m/s, and two have speeds of 12.0 m/s. find (a) the average speed, (b) the rms speed, and (c) the most probable speed of these particles.
Physics
1 answer:
Tems11 [23]3 years ago
5 0
A. Average speed is weighted mean (1 × 2 + 2 × 3 + 3 × 5 + 4 × 7 + 3 × 9 + 2 × 12.5)/15 = (2 + 6 + 15 + 28 + 27 + 25)/15 = 103/15 = 6.867 b. RMS is square root of 1/15 times sum of squares of speeds Sum of squares is 4 + 9 + 9 + 25 + 25 + 25 + 49 + 49 + 49 + 49 + 81 + 81 + 81 +156.25 + 156.25 = 848.5 
c. RMS speed = √(848.5/15) = 7.521 
Most likely the speed is the peak in the speed distribution, which is 7.
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Boyle’s Law states that when a sample of gas is compressed at a constant temperature, the pressure P of the gas is inversely pro
jolli1 [7]

Answer:

a)V=\dfrac{5.3}{P}

b)ML^{-4}T^{-2}.

Explanation:

Given that

Boyle's law

P V = Constant ,at constant temperature

a)

Given that

P_1=50KPa

V_1=0.106m^3

We know that for PV=C

P_1V_1=P_2V_2=PV

Now by putting the values

PV= 50 x 0.106

V=\dfrac{5.3}{P}

Where P is in KPa and V is in m^3

b)

PV= C

Take ln both sides

So \ln(PV)=\ln C

lnP + lnV =lnC               ( C is constant)

By differentiating

\dfrac{dP}{P}+\dfrac{dV}{V}=0

So

\dfrac{dP}{dV}=-\dfrac{P}{V}

When P= 50 KPa

\dfrac{dP}{dV}=-\dfrac{50}{V}\ \dfrac{KPa}{m^3}

It indicates the slope of PV=C curve.

It unit is \dfrac{Pa}{m^3}.

Or we can say that ML^{-4}T^{-2}.

5 0
3 years ago
Read 2 more answers
Please help me with the following question:
pishuonlain [190]

Answer: a. 667N

b. 665N

c. 54.5N

Explanation:

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W = mg

W = 68 × 9.81

= 667N

b) at the top of Everest (8848 m above sea level).

W =mg × R²/(R + H)²

W = 667 × [6378²/(6378 + 8.848)²

W = 665N

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W = mg × R²/(R + H)²

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W = 54.5N

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5 0
3 years ago
a balloon inflated in a room at 297k has a volume of 4.00 l. the balloon is then heated to a temperature of 331 k. what is the n
Naddika [18.5K]
V2 = 4.4579 L

Since pressure is constant, use Charle’s law.
Charles's law, a statement that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

V(olume) 1 = V(olume) 2
————— —————
T(emperature) 1 T(emperature)2

4.00 L = V2
———- ———
297 K 331 K

Cross multiply
(4.00 L x 331 K) = (297 K x V2)
Simplify
1324 L/K = 297 K x V2
Isolate V2 by dividing out 297 K
1324 L/K = V2
————
297 K
(This cancels out the kelvin and leaves you with Liters as the volume measure)

V2 = 4.4579 L

Round to significant digits if required
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How remove local action and polarization ​
slava [35]

Answer:

Local action is removed by amalgamating zinc rod.

Explanation:

This prevents chemical reaction to occur because impurities in the zinc cannot get into contact with an electrolyte.

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