from farthest to the nearest
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Uranus
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mercury
Answer is d 30 m/s, North
Given: Distance d = 60 m; Time t = 2 seconds
Required: Average Velocity Vave. Vi + Vf/2
Formula: d = 1/2 at² derive acceleration a = ? and a = Vf - Vi/t
a = 2d/t²
a = 1/2(60 m)/( 2 s)²
a = 30 m/s²
Solve for final Velocity Vf = ?
a = Vf -Vi/t
Vf = at Since Initial Velocity is zero
Vf = (30 m/s²)(2 s)
Vf = 60 S
For average velocity Vave. = Vi + Vf/2
Vave. 0 + 60 m/s/2
Vave = 30 m/s North.
Answer:
ΔL = 0.429 m
Explanation:
The expression for linear thermal expansion is
ΔL = α L₀ ΔT
the coefficient of linear expansion of steel is 11 10⁻⁶ ºC⁻¹
the initial length of the bridge is L₀ = 1.30 10³ m and the temperature variation is ΔT = 30 ºC
calculate
ΔL = 11 10⁻⁶ 1.30 10³ 30
ΔL = 4.29 10⁻¹ m
ΔL = 0.429 m
We have that the force between the two charged objects is mathematically given as
F=2.349N
<h3>Magnitude of the force between two charged objects.</h3>
Question Parameters:
Two spheres carry a charge of 1x10^-7 C.
Their centers are <u>separated</u> by 0.7m.
Generally the equation for the Force is mathematically given as
Therefore
F=2.349N
For more information on Force visit
brainly.com/question/26115859
The equation for power is P=w/t, where w=work done in joules and t=time in seconds.
in this case:
p=w/t
p=3500/25
p=140
so, the boat was using 140 watts of power.
