It varies with container, temperature, pressure and amount of gas. But, the volume occupied by a gas at a fixed temperature and pressure remains constant which is 22.4 L for 1 mole at STP.
Answer:
Composed of a phospholipid bilayer with embedded proteins, the plasma membrane is selectively permeable to ions and organic molecules and regulates the movement of substances in and out of cells. The membrane also maintains the cell potential.
Explanation:
(see above)
Answer:
a.Phenols have the ability to spread out the negative charge that forms.
Explanation:
This happens because of the aromatic ring the phenols have. When loosing the proton, the anion formed have different resonance isomers due to the double bonds in the aromatic ring. This resonance makes the anion more stable and prevents the reaction going backwards.
On the other hand, regular alcohol doesn't have resonace and the reaction of loosing the proton goes leftward and righward: is in equilibrium.
That equilibrium decreases the acidity of the alcohol.
Answer:
1.75M
Explanation:
The problem deals with finding the molarity of the given compound.
The compound is:
Na₂SO₄.10H₂O
Mass of the compound = 10.5kg = 10500g
Volume of the compound = 18.6L
Molarity is the number of moles of solute in a solution;
Molarity =
Number of moles =
Molar mass of Na₂SO₄.10H₂O = 2(23) + 32 + 4(16) + 10[2(1) + 16]
= 322g/mol
Now;
Number of moles =
= 32.6mole
So;
Molarity =
= 1.75M
Answer:
0.03697 mol Al₂(SO₄)₃
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
12.65 g Al₂(SO₄)₃
<u>Step 2: Identify Conversions</u>
Molar Mass of Al - 26.98 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Al₂(SO₄)₃ - 2(26.98) + 3(32.07) + 12(16.00) = 342.17 g/mol
<u>Step 3: Convert</u>
<u />
= 0.03697 mol Al₂(SO₄)₃
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig fig rules and round.</em>
We already have 4 sig figs in the final answer, so no need to round.