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Sedbober [7]
3 years ago
8

A student used a tuning fork of frequency 320 Hz and observed that the speed of sound was 339 m/s. Calculate the wavelength of t

his sound wave (in m). (Enter your answer to at least three significant figures.)
Physics
1 answer:
Helen [10]3 years ago
5 0

To solve this problem it is necessary to apply the concepts related to wavelength as a function of speed and frequency. In mathematical terms it can be expressed as

\lambda = \frac{v}{f}

Where,

v = Velocity

f = Frequency

According to our values the frequency (f) is 320Hz and the speed (v) is 339m / s.

Replacing in the given equation we have to,

\lambda = \frac{v}{f}\\\lambda = \frac{339}{320}\\\lambda = 1.059m\approx 1.06m

Therefore the wavelength of this sound wave is 1.06m

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Two identical capacitors are connected parallel. Initially they are charged to a potential V0 and each acquired a charge Q0. The
MrRa [10]

Answer:

Explanation:

capacitance of each capacitor

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V₀ = Q₀ / C₀

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2 V₀ / ( 1 + K )

b )

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6 0
3 years ago
A rectangular key was used in a pulley connected to a line shaft with a power of 7.46 kW at a speed of 1200 rpm. If the shearing
Damm [24]

Given:

Shaft Power, P = 7.46 kW = 7460 W

Speed, N = 1200 rpm

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Shearing stress of key, \tau _{key} = 240 MPa

width of key, w = \frac{d}{4}

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Solution:

Torque, T = \frac{P}{\omega }

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\omega = \frac{2\pi  N}{60}

T = \frac{7460}{\frac{2\pi  (1200 )}{60}} = 59.365 N-m

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30\times 10^{6} = \frac{2\times 59.365}{\pi (\frac{d}{2})^{3}}

d = 0.0216 m

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w =  \frac{d}{4} =  \frac{0.02116}{4} = 5.4 mm

Now, for shear stress in key

\tau _{key} = \frac{F}{wl}

we know that

T = F \times r =  F. \frac{d}{2}

⇒ \tau _{key} = \frac{\frac{T}{\frac{d}{2}}}{wl}

⇒ 240\times 10^{6} = \frac{\frac{59.365}{\frac{0.0216}{2}}}{0.054l}

length of the rectangular key, l = 4.078 mm

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3 years ago
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4 0
3 years ago
A bird flies with a constant velocity of 100m/s for 10 minutes. calculate the magnitude of the displacement.​
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