A bird flies with a constant velocity of 100m/s for 10 minutes. calculate the magnitude of the displacement.
2 answers:
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Answer:
The time for final 15 cm of the jump equals 0.1423 seconds.
Explanation:
The initial velocity required by the basketball player to be able to jump 76 cm can be found using the third equation of kinematics as
where
'v' is the final velocity of the player
'u' is the initial velocity of the player
'a' is acceleration due to gravity
's' is the height the player jumps
Since the final velocity at the maximum height should be 0 thus applying the values in the above equation we get
Now the veocity of the palyer after he cover'sthe initial 61 cm of his journey can be similarly found as
Thus the time for the final 15 cm of the jump can be found by the first equation of kinematics as
where symbols have the usual meaning
Applying the given values we get
Answer:
The air temperature at the tropopause is - 79 °C
Explanation:
We know that a station near the equator has a surface temperature of 25°C
Vertical soundings reveal an environmental lapse rate of 6.5 °C per kilometer.
The tropopause is encountered at 16 km.
In order to find the air temperature at the tropopause we are going to deduce a linear function for the temperature at the tropopause.
This linear function will have the following structure :
Where '''' and ''
'' are real numbers.
Let's write to denote the temperature '' T '' in function of the distance
'' x '' ⇒
We can reorder the function as :
(I)
Now, at the surface the value of '''' is 0 km and the temperature is 25°C so in the function (I) we write :
⇒
⇒
(II)
In (II) the value of '''' represents the change in temperature per kilometer.
Because the temperature decrease with the height this number will be negative and also a data from the question ⇒
(III)
In (III) we deduced the linear equation. The last step is to replace by in (III) ⇒
The air temperature at the tropopause is - 79 °C