Answer:
Explanation:
The problem is related to rotational motion . So we shall find out rotational kinetic energy .
K E = 1/2 x I ω²
ω is the final angular velocity
Moment of inertial of the disk
I ₁ = 1/2 m r²
= .5 x 165 x 2.93²
= 708.25 kgm²
Moment of inertial of the person
I₂ = mr²
= 62.5 x 2.93²
= 536.55 kgm²
ω₂ = v / R
= 3.11 / 2.93 rad /s
At the time of jumping , law of conservation of angular momentum will apply
I₁ ω₁ + I₂ω₂ = (I₁ + I₂)ω
708.25 x0.691 + 536.55 x ( 3.11 / 2.93 ) = ( 708.25 + 536.55 ) ω
ω = 0 .85 rad/ s
K E = 1/2 x I ω²
= .5 x ( 708.25 + 536.55 ) ( .85 )²
449.68 J
Answer: 178.25*10^-6 T
Explanation: In order to solve this problem we have to take into account the equilibrium between the electric and magnetic forces in the electron, so it is given by:
Fm=evB
Fe=eE so
evB=eE the we have
v=E/B
Firsly we calculate the velocity of the electron before to get the parallel plates at 100V
eΔV=1/2*m*v^2 then
v=(2*eΔV/m)^1/2
v=(2*1.6*10^-19*3.1*10^3/9.1*10^-31)^1/2=33 *10^6 m/s
Then we can calculate B
B=E/v E.d=V where d is the separation between the plates and V is equal a 100V
B=V/(d*v)=100/(17*10^-3*33 *10^6)=178.25*10^-6 T
Let's find the relationship
- So if frequency increases Energy of the wave increases and wavelength decreases and vice-versa
Answer:
Explanation:
= 14 km
= 49 km
Intensity of a wave is inversely proportional to distance
So,
The ratio of the intensities is
