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Vladimir [108]
3 years ago
10

An 4-kg ball experiences a force and accelerates at a rate of 1.5 m/s.

Physics
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

6.0 N

Explanation:

The strength of a force is expressed as the magnitude of the force in Newton.

The formula to apply here is :

Force= mass * acceleration

F=ma

Mass, m = 4 kg

Acceleration = 1.5 m/s²

Force= 4 *1.5 = 6.0 N

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Velocityis a vector quantity which has both magnitude and direction. Using complete sentences, describethe object's velocity. Co
mr_godi [17]

Answer:

Explanation:

A physical quantity which can be completely described by the magnitude and direction both are called vector quantities. For example, displacement, velocity, etc.

A physical quantity which can be completely explained by the magnitude only is called scalar quantity. For example, mass, time, etc.

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3 years ago
__________energy might also be released during a chemical reaction
pentagon [3]
Kinetic energy i think
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What is the velocity of a car that travels -50 meters in 5 seconds then 10 meters in 5 seconds
diamong [38]

Answer:

2 m/s

Explanation:

The first part of the question the car is going in reverse or negative along the x axis. Then the second part the car is moving forward along the x axis. So the car would only have velocity in the current direction of movement. So our equation for velocity is as follows.

v = d/t

v = 10 m/5 s

v = 2 m/s

3 0
3 years ago
A stone is thrown vertically upwards with an initial velocity of 20m/sec. Find the maximum height ot reaches and the time taken
MAXImum [283]

Answer:

The height reached is 20m, The time taken to reach 20m is 2 seconds

Explanation:

Observing the equations of motion we can see that the following equation will be most helpful for this question.

v^{2} = u^{2} + 2as

We are given initial velocity, u

We know that the stone will stop at its maximum height, so final velocity, v

Acceleration, a

And we are looking for the displacement (height reached), s

Substitute the values we are given into the equation

0^{2} = 20^{2} + 2(10)s

Rearrange for s

0^{2} -20^{2} =20s

-400=20s

\frac{-400}{20} =s

s = -20 (The negative is just showing direction, it can be ignored for now)

The height reached is 20m

Use a different equation to find the time taken

s = vt - \frac{1}{2} at^{2}

Substitute in the values we have

-20=(0)t - \frac{1}{2} (10)t^{2}

Rearrange for t

-20 =0 -5 t^{2}

\frac{-20}{-5} =t^{2}

4 = t^{2}

t = 2s

The time taken to reach 20m is 2 seconds

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3 years ago
PLEASE HELP. I WILL MARK BRAINIEST
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Aaaaaaaaaaaaaaaaaaaaaaaa
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