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Arte-miy333 [17]
3 years ago
13

2log_(4)(-8.75)+6log_(4)(6.81)-5log_(4)(11.83)

Mathematics
1 answer:
DochEvi [55]3 years ago
5 0

Answer:

I think it would be -21.55 if you are rounding to the hundredths

Step-by-step explanation:

Put it in the calculator!! Hope I helped you! Sorry if I make you get it wrong!!

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musickatia [10]
How do i solve 6x-12=36

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Using the chart above, find the total amount and amount of interest paid in the following compound interest problems.
gizmo_the_mogwai [7]

Answer:

Annually: Total Amount = 1611.76, Interest Amount = 711.76

Semiannually: Total Amount = 1625.50 , Interest Amount = 725.50

Quarterly: Total Amount = 1632.62 , Interest Amount = 732.62

Step by Step Explanation:

We can see from the table that the factor that we need to multiply with 900 in order to get amount for compounded annually is 1.7908477. Therefore, our total amount is 1.7908477*900 = 1611.76 and interest earned is 1611.76-900 = 711.76.

The factor that we need to multiply with 900 in order to get amount for compounded semiannually is 1.8061112. Therefore, our total amount is 1.8061112*900 = 1625.50 and interest earned is 1625.50-900 = 725.50.

The factor that we need to multiply with 900 in order to get amount for compounded semiannually is 1.8140184. Therefore, our total amount is 1.8140184*900 = 1632.62 and interest earned is 1632.62-900 = 732.62.

6 0
3 years ago
Please help i’m not understanding
ratelena [41]

Answer:

D is not a supported statement

Step-by-step explanation:

Let take them one by one:

A: from table: 0.57; in statement: 0.5

0.57 > 0.5 so this is supported

B: from table: 0.2+0.16=0.36; in statement: 1/3=0.33,

0.36>0.33 so this is supported

C: 0.07 is the least, so this is supported

D: the table DOES NOT show number of students, but proportions. So statement '7 students' IS NOT supported

E: from table 0.20 overslept. 0.2 < 1/4=0.25, so this is supported

8 0
3 years ago
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schepotkina [342]

Answer:

What's the question?

Step-by-step explanation:

Your struggling with

7 0
3 years ago
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