Question

When a quarterback throws a football, the throwing arm is slowed down to rest during the deceleration phase. Of the angular velocity of the throwing arm is 1800 deg/sec at the instant of ball release, then how much would the arm deceleration change if the deceleration was reduced from 2 sec to 0.5 sec

Answer 1

Answer:

The deceleration is 4 times higher for 0.5sec than for 2 sec.

Explanation:

If the deceleration happens from 1800deg/sec to zero in 2 sec we have that the magnitude is:

$a_{1}=w/t_{1}=(1800deg/sec)/2sec=900 deg/sec^{2}$

if now the time to decelerate is 0.5sec:

$a_{2}=w/t_{2}=(1800deg/sec)/0.5sec=3600 deg/sec^{2}$

The deceleration is now 4 times higher than the previous situation.