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podryga [215]
3 years ago
13

Now consider a different time interval: the interval between the initial kick and the moment when the ball reaches its highest p

oint. We want to find how long it takes for the ball to reach this point, and how high the ball goes. (e) What is the component of the ball’s velocity at the instant when the ball reaches its highest point (the end of this time interval)?
Physics
1 answer:
scZoUnD [109]3 years ago
3 0

Answer:A ball is kicked from a location < 9, 0, -8 > (on the ground) with initial velocity < -11, 18, -5 > m/s. The ball's speed is low enough that air resistance is negligible. What is the velocity of the ball 0.5 seconds after being kicked? (Use the Momentum Principle!) = m/s In this situation (constant force), which velocity will give the most accurate value for the location of the ball 0.5 seconds after it is kicked? The arithmetic average of the initial and final velocities. The final velocity of the ball. The initial velocity of the ball. What is the average velocity of the ball over this time interval? avg = Use the average velocity to find the location of the ball 0.5 seconds after being kicked: = m Now consider a different time interval: the interval between the initial kick and the moment when the ball reaches its highest point. We want to find how long it takes for the ball to reach this point, and how high the ball goes. What is the y-component of the ball's velocity at the instant when the ball reaches its highest point (the end of this time interval)? vyf = m/s. Fill in the missing numbers in the equation below (update form of the Momentum Principle): mvyf = mvyi + Fnet,y?t m = m + ?mg?t How long does it take for the ball to reach its highest point? ?t = s. Knowing this time, first find the y-component of the average velocity during this time interval, then use it to find the maximum height attained by the ball: ymax = m. Now take a moment to reflect on the reasoning used to solve this problem. You should be able to do a similar problem on your own, without prompting. Note that the only equations needed were the Momentum Principle and the expression for the arithmetic average velocity.

Explanation:

You might be interested in
a 1600 kg car on flat ground is moving 6.25 m/s. its engine creates 1150 N forward force as the car moves 45.8 m. what is it fin
Sveta_85 [38]

Answer:

83,900 J

Explanation:

First, find the acceleration:

F = ma

1150 N = (1600 kg) a

a = 0.719 m/s²

Now find the final velocity.

Given:

Δx = 45.8 m

v₀ = 6.25 m/s

a = 0.719 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (6.25 m/s)² + 2 (0.719 m/s²) (45.8 m)

v = 10.2 m/s

Now find the final KE:

KE = ½ mv²

KE = ½ (1600 kg) (10.2 m/s)²

KE = 83,920 J

Rounded to three significant figures, the final kinetic energy is 83,900 J.

6 0
4 years ago
A 55.0-g sample of hot metal initially at 99.5oC was added to 40.0 g of water in a Styrofoam coffee cup calorimeter. The water a
Kaylis [27]

Answer:

Cp= 0.44 J/g.C

This is heat capacity of metal.

Explanation:

From energy conservation

Heat lost by metal = Heat gain by water +Heat gain by  calorimeter

Because here temperature of metal is high that is why it loose the heat.The temperature of water and  calorimeter is low that is why they gain the heat.

final temperature is T= 30.5 C

We know that sensible heat transfer given as

Q= m Cp ΔT

m=Mass

Cp=Specific heat capacity

ΔT=Temperature difference

By putting the values

55 x Cp ( 99.5 - 30.5) = 40 x 4.184 ( 30.5- 21 ) + 10 x ( 30.5 - 21)

Cp ( 99 .5- 30.5) = 30.65

Cp= 0.44 J/g.C

This is heat capacity of metal.

4 0
4 years ago
Consider a golf ball with a mass of 45.9 grams traveling at 200 km/hr. If an experiment is designed to measure the position of t
Kipish [7]

Answer:

speed of golf ball is 1.15 × 10^{-30} m/s

and % of uncertainty in speed =  2.07 × 10^{-30} %

Explanation:

given data

mass = 45.9 gram = 0.0459 kg

speed = 200 km/hr = 55.5 m/s

uncertainty position Δx = 1 mm = 10^{-3} m

to find out

speed of the golf ball and  % of speed of the golf ball

solution

we will apply here heisenberg uncertainty principle that is

uncertainty position ×uncertainty momentum ≥ \frac{h}{4\pi }    ......1

Δx × ΔPx  ≥ \frac{h}{4\pi }

here uncertainty momentum ΔPx = mΔVx

and uncertainty velocity = ΔVx

and h = 6.626 × 10^{-34} Js

so put here all these value in equation 1

10^{-3} × 0.0459 × ΔVx =  \frac{6.626*10^{-34}}{4\pi }

ΔVx = 1.15 × 10^{-30} m/s

and

so % of uncertainty in speed = ΔV / m

% of uncertainty in speed =  1.15 × 10^{-30}  / 55.5

% of uncertainty in speed =  2.07 × 10^{-30} %

3 0
4 years ago
What is one way that nuclear fusion differs from nuclear fission?
Bezzdna [24]

Answer:

A. Nuclear fusion requires very high pressures and temperatures.

Explanation:

8 0
3 years ago
Read 2 more answers
Which of the following is true regarding transverse waves?
DIA [1.3K]

Answer:

in a transverse wave, The directions that energy and matter travel in are perpendicular to one another.

these waves are types of mechanical waves that doesn't require any material medium to transfer.

4 0
3 years ago
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