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podryga [215]
3 years ago
13

Now consider a different time interval: the interval between the initial kick and the moment when the ball reaches its highest p

oint. We want to find how long it takes for the ball to reach this point, and how high the ball goes. (e) What is the component of the ball’s velocity at the instant when the ball reaches its highest point (the end of this time interval)?
Physics
1 answer:
scZoUnD [109]3 years ago
3 0

Answer:A ball is kicked from a location < 9, 0, -8 > (on the ground) with initial velocity < -11, 18, -5 > m/s. The ball's speed is low enough that air resistance is negligible. What is the velocity of the ball 0.5 seconds after being kicked? (Use the Momentum Principle!) = m/s In this situation (constant force), which velocity will give the most accurate value for the location of the ball 0.5 seconds after it is kicked? The arithmetic average of the initial and final velocities. The final velocity of the ball. The initial velocity of the ball. What is the average velocity of the ball over this time interval? avg = Use the average velocity to find the location of the ball 0.5 seconds after being kicked: = m Now consider a different time interval: the interval between the initial kick and the moment when the ball reaches its highest point. We want to find how long it takes for the ball to reach this point, and how high the ball goes. What is the y-component of the ball's velocity at the instant when the ball reaches its highest point (the end of this time interval)? vyf = m/s. Fill in the missing numbers in the equation below (update form of the Momentum Principle): mvyf = mvyi + Fnet,y?t m = m + ?mg?t How long does it take for the ball to reach its highest point? ?t = s. Knowing this time, first find the y-component of the average velocity during this time interval, then use it to find the maximum height attained by the ball: ymax = m. Now take a moment to reflect on the reasoning used to solve this problem. You should be able to do a similar problem on your own, without prompting. Note that the only equations needed were the Momentum Principle and the expression for the arithmetic average velocity.

Explanation:

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The magnetic field at the equator points north. If you throw a positively charged object (for example, a baseball with some elec
PilotLPTM [1.2K]

Answer:

The magnetic force points in the positive z-direction, which corresponds to the upward direction.

Option 2 is correct, the force points in the upwards direction.

Explanation:

The magnetic force on any charge is given as the cross product of qv and B

F = qv × B

where q = charge on the ball thrown = +q (Since it is positively charged)

v = velocity of the charged ball = (+vî) (velocity is in the eastern direction)

B = Magnetic field = (+Bj) (Magnetic field is in the northern direction; pointing forward)

F = qv × B = (+qvî) × (Bj)

F =

| î j k |

| qv 0 0|

| 0 B 0

F = i(0 - 0) - j(0 - 0) + k(qvB - 0)

F = (qvB)k N

The force is in the z-direction.

We could also use the right hand rule; if we point the index finger east (direction of the velocity), the middle finger northwards (direction of the magnetic field), the thumb points in the upward direction (direction of the magnetic force). Hence, the magnetic force is acting upwards, in the positive z-direction too.

Hope this Helps!!!

5 0
3 years ago
Why does it take much longer time and distance to stop a moving ship in water than a moving car on the road
Naddik [55]
The force on the ship is more than a car
6 0
3 years ago
How is a projectile different from an object in free fall
aksik [14]

Answer:

Explanation:

Projectile Motion. Projectile motion is different than free fall: it involves two dimensions instead of one. ... Balls traveling in two dimensions, only one of which experiences acceleration, require two sets of equations: one set for the x-direction and the other for the y-direction.

7 0
3 years ago
The spectra of most stars are dark-line spectra because ________.
pav-90 [236]
Because dark line spectra result from passing white light through ionized gasses and plasmas, which is what the atmosphere of stars are made of.  These frequencies are scattered by the star's atmosphere as it leaves the surface (photosphere) of the star, and don't make it to earth.
5 0
3 years ago
A circular loop of wire is in the plane of the paper. The south pole of a bar magnet is being moved from a position in front of
drek231 [11]

Answer:

Counterclockwise

explanation in attachment

5 0
3 years ago
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