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Tamiku [17]
3 years ago
10

how much power does an electric device use if the current is 36.0 amps and the resistance is 3.9 ohms? a. 140 watts b. 5,100 wat

ts c. 550 watts d. 9.2 watts
Physics
1 answer:
kakasveta [241]3 years ago
5 0
P = I²R          

where P = Power in Watts, I = Current in Ampere, R = Resistance in ohms.

P = 36<span>² * 3.9 = 5054.4
 
P </span>≈ 5100 watts.
<span>
Option B.  </span>
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Three charged particles are positioned in the xy plane: a 50-nC charge at y = 6 m on the y axis, a –80-nC charge at x = –4 m on
leva [86]

Answer:48 V

Explanation:

Given

Three charged particle with charge

q_1=50\ nC at y=6\ m

q_2=-80\ nC at x=-4\ m

q_3=70\ nC at y=-6\ m

Electric Potential is given by

V=\frac{kQ}{r}

Distance of q_1 from x=8\ m

d_1=\sqrt{6^2+8^2}

d_1=\sqrt{36+64}

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similarly d_2=8-(-4)

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d_3=\sqrt{(-6)^2+8^2}

d_3=\sqrt{36+64}

d_3=10\ m

Potential at x=8\ m is

V_{net}=\frac{kq_1}{d_1}+\frac{kq_2}{d_2}+\frac{kq_3}{d_3}

V_{net}=k[\frac{q_1}{d_1}+\frac{q_2}{d_2}+\frac{q_3}{d_3}]

V_{net}=9\times 10^9[\frac{50}{10}-\frac{80}{12}+\frac{70}{10}]\times 10^{-9}

V_{net}=9\times 5.33

V_{net}=47.97\approx 48\ V

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3 years ago
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