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Tamiku [17]
3 years ago
10

how much power does an electric device use if the current is 36.0 amps and the resistance is 3.9 ohms? a. 140 watts b. 5,100 wat

ts c. 550 watts d. 9.2 watts
Physics
1 answer:
kakasveta [241]3 years ago
5 0
P = I²R          

where P = Power in Watts, I = Current in Ampere, R = Resistance in ohms.

P = 36<span>² * 3.9 = 5054.4
 
P </span>≈ 5100 watts.
<span>
Option B.  </span>
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Dahasolnce [82]

Answer:

b = - a - c + p

Explanation:

P= a+b+c : move the b over to the other side.

-b + p = a + c : move p over the other side.

-b = a + c - p : now just convert the a + c - p into,

b = -a - c + p

8 0
4 years ago
Grain is pouring into a silo to be stored for later use. Due to the friction between pieces of grain as they rub against each ot
jolli1 [7]

Answer:

The electric force between them if the pieces of grain are 2 cm apart is 3.15\times 10^{-11}\textrm{ N}.

Explanation:

Given:

Charge on one grain, Q_{1}=6\times 10^{-10}\textrm{ C}

Charge on another grain, Q_{2}=2.3\times 10^{-15}\textrm{ C}

Separation between them, d=2\textrm{ cm}=0.02\textrm{ m}

Electric force acting between two charges Q_{1}\textrm{ and }Q_{2} separated by a distance d is given as:

F_{elec}=\frac{kQ_{1}Q_{2}}{d^2}

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Now, plug in all the values and solve for F{elec}.

F{elec}=\frac{9\times 10^9\times 6.0\times 10^{-10}\times 2.3\times 10^{-15}}{(0.02)^2}\\\\F_{elec}=3.15\times 10^{-11}\textrm{ N}

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3 0
3 years ago
1) Halving the distance (i.s., decreasing by a factor of two) between two charged objects will cause the electrical force betwee
Vedmedyk [2.9K]

Answer:

Explanation:

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F = kQq/r^2

Given:

r2 = 1/2 × r1

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F1 × r1 = F2 × r2

F2 = (F1 × r1^2)/(0.5 × r1)^2

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7 0
4 years ago
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Answer:

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Explanation:

The free-body  diagram below shows the interpretation of the question; from the diagram , the wheel that is rolling in a clockwise directio will have two velocities at point P;

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3 years ago
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