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aev [14]
3 years ago
11

The magnetic field at the equator points north. If you throw a positively charged object (for example, a baseball with some elec

trons removed) to the east, what is the direction of the magnetic force on the object? 1. Toward the east 2. Upward 3. Toward the west 4. Downward
Physics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0

Answer:

The magnetic force points in the positive z-direction, which corresponds to the upward direction.

Option 2 is correct, the force points in the upwards direction.

Explanation:

The magnetic force on any charge is given as the cross product of qv and B

F = qv × B

where q = charge on the ball thrown = +q (Since it is positively charged)

v = velocity of the charged ball = (+vî) (velocity is in the eastern direction)

B = Magnetic field = (+Bj) (Magnetic field is in the northern direction; pointing forward)

F = qv × B = (+qvî) × (Bj)

F =

| î j k |

| qv 0 0|

| 0 B 0

F = i(0 - 0) - j(0 - 0) + k(qvB - 0)

F = (qvB)k N

The force is in the z-direction.

We could also use the right hand rule; if we point the index finger east (direction of the velocity), the middle finger northwards (direction of the magnetic field), the thumb points in the upward direction (direction of the magnetic force). Hence, the magnetic force is acting upwards, in the positive z-direction too.

Hope this Helps!!!

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A 2.0 m × 4.0 m flat carpet acquires a uniformly distributed charge of −10 μC after you and your friends walk across it several
mamaluj [8]

Answer:

The  charge on the dust particle is  q_d  = 6.94 *10^{-13} \  C

Explanation:

From the question we are told that

    The length is  l = 2.0 \ m

    The width is  w = 4.0 \ m

   The charge is  q =  -10\mu C= -10*10^{-6} \ C

    The mass suspended in mid-air is m_a =  5.0 \mu g =  5.0 *10^{-6} \ g =  5.0 *10^{-9} \  kg

   

Generally the electric field on the carpet is mathematically represented as

           E =  \frac{q}{ 2 *  A  *  \epsilon _o}

Where \epsilon _o is the permittivity of free space with value \epsilon_o = 8.85*10^{-12}  \ \  m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

substituting values

           E =  \frac{-10*10^{-6}}{ 2 *  (2 * 4 )  *  8.85*10^{-12}}

           E = -70621.5 \  N/C

Generally the electric force keeping the dust particle on the air  equal to the force of gravity acting on the particles

        F__{E}} =  F__{G}}

=>     q_d *  E  =  m * g

=>      q_d  =  \frac{m * g}{E}

=>      q_d  =  \frac{5.0 *10^{-9} * 9.8}{70621.5}

=>     q_d  = 6.94 *10^{-13} \  C

4 0
3 years ago
1. A wave has a wavelength of 5 m and a frequency of 2 Hz. At what speed/velocity does the
yuradex [85]

Answer:

1.10m/s

2.0.1m

3.5Hz

Explanation:

v=velocity, f=frequency and T=wavelength

1.v=ft

v=2x5

=10m

2.v=ft

100=1000T

divide both sides by 1000

T=0.1m

3.v=fT

25=5f

divide both sides by 5

f=5Hz

4 0
2 years ago
The Position Of A Particle Moving In The Xy Plane Is Given By R= [2.0*cos(3.0t)i+ 2.0*sin(3.0t)j] Where R Is In Meters And T Is
ExtremeBDS [4]

Answer:

Explanation:

We can prove that this is a circular motion if we demonstrate that the norm of the vector is independent of time. Hence we have

R(t)=2.0cos(3t)\hat{i}+2sin(3t)\hat j\\\\|R(t)|=\sqrt{4cos^2(3t)+4sin^2(3t)}\\\\|R(t)|=\sqrt{4(cos^2(3t)+sin^2(3t))}\\\\

but cos^2(3t)+sin^2(3t)=1. Thus we obtain

|R(t)|=\sqrt{4}=2

The norm is independent of t, thus, the particle describes a circular motion

Hope this helps!!

3 0
3 years ago
Is it possible to do work on an object without changing the kinetic energy of the object? Now Why?
Murrr4er [49]

Answer:

(a) Yes, it is possible by raising the object to a greater height without acceleration.

Explanation:

The work-energy theorem states that work done on an object is equal to the change in kinetic energy, and change in  kinetic energy requires a change in velocity.

If kinetic energy will not change, then velocity will not change, this means that there will be constant velocity and an object with a constant velocity is not accelerating.

If the object is not accelerating (without acceleration) and it remains at the same height (change in height = 0, and mgh = 0).

Thus, for work to be done on the object, without changing the kinetic energy of the object, the object must be raised  to a greater height without acceleration.

Correct option is " (a) Yes, it is possible by raising the object to a greater height without acceleration".

8 0
3 years ago
A wave transfers _____ from the source outward in the direction of wave motion.
Angelina_Jolie [31]

Answer

b. energy

Explanation:

wave is a disturbance that carries energy from one particle to another particle.

4 0
3 years ago
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