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3 years ago

Which is true about equivalent fractions?

1 answer:

3 0

They have the same value even though their numerator and denominator are different. For example, 8/16 and 1/2 are equivalent fractions which both represent 0.5.

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Use mathematical induction to prove that if L is a linear transformation from V to W, then L (α1v1 + α2v2 +· · ·+αnvn)= α1L (v1)

e-lub [12.9K]

Answer:

The proof is shown in the explanation below.

Step-by-step explanation:

Analysis:

The proof by induction focuses on n. In this case, let n = 1, and $L^{1}$ will be a linear operator since $L^{1} = L$

The exercise will show that $L^{n}$ is a linear operator on V and that $L^{n+1}$ is also a linear operator on V. This, follows that:

$L^{n+1} (av) = L(L^{m}(v_{1}+v_{2})\\ = L(L^{m} (v_{1} + L^{m}v_{2})\\ = L(L^{m}v_{1} + L(L^{m}v_{2})\\ = L^{m+1}(v_{1}) + L^{m+1}(v_{2})$

6 0

3 years ago

Read 2 more answers

Move the numbers to the blanks to order from least to greatest value

lakkis [162]

-.89, .4, 1/2, 9/8, |-2|

5 0

3 years ago

How do you solve 7n-2=6n-2n

pantera1 [17]

First combine like terms:
6n-2n = 4n
7n-2=4n
subtract 7n from both sides
7n-2=4n
-7n -7n
-2=-3n
divide -2 on both sides.
n=1.5

7 0

3 years ago

Find the distance between each pair of points<br> 8) (2, 6), (5, 10)<br> 9) (-3,-10), (-3,5)

Lapatulllka [165]

Answer:

8) answer=5 9)answer=15

Step-by-step explanation:

all you have to do is replace in the following formula

$\sqrt{(x2-x1)^{2}+ (y2-y1)^{2}} =d$

Where

X1: is the first number of the first point

Y1: is the second number of the first point

X2: is the first number of the second point

Y2: is the second number of the second point

you replace in the formula and solve

I attach solution

4 0

3 years ago

What is the slope of the line?

Ann [662]

Answer:

m= 8/5

Step-by-step explanation:

Points on the graph: ( -4, -4) and (1, 4)

Slope:

m=(y2-y1)/(x2-x1)

m=(4+4)/(1+4)

m= 8/5

4 0

3 years ago

Read 2 more answers