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2 years ago

Determine la temperatura Kelvin de 2.49 moles de gas contenido en un

1 answer:

7 0

La temperatura del gas contenido en el recipiente es de -259,35 ° C
Explicación:
Para encontrar la unidad de grados en Celsius (° C) en este caso, se usa la ecuación de la ley de los gases ideales.
PV = nRT
Donde P es la presión, V es el volumen, T es la temperatura, n es el número de moles y R es la constante universal de los gases.
P = 143 kPa = 1,4113 atmósferas
V = 2,00 L
n = 2,49 mol
R = 0.08205746 atm * L / mol * K
Resolver para T sería: PV / nR
T = (1.4113 atm * 2.00 L) / (2.49 mol * 0.08205746 atm * L / mol * K)
T = 2,8226 / 0,2043
T = 13,8 K = -259,35 ° C

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How many grams are in 5.2 moles of Li2SO4

skelet666 [1.2K]

Answer:

572 g

Explanation:

Molar mass is the mass of 1 mol of an element or compound

molar mass of Li₂SO₄ is the sum of the products of the molar masses of the elements by the number of atoms in the compound

molar masses of each element making up lithium sulphate

Li - 7 g/mol

S - 32 g/mol

O - 16 g/mol

molar mass of Li₂SO₄ - (7 g/mol x 2) + ( 32 g/mol x 1) + ( 16 g/mol x 4 )

molar mass = 110 g/mol

mass of 1 mol of Li₂SO₄ is 110 g

therefore mass of 5.2 mol of Li₂SO₄ is - 110 g/mol x 5.2 mol = 572 g

mass is 572 g

7 0

3 years ago

The equilibrium constant Kc for the reaction PCl3(g) + Cl2(g) ⇌ PCl5(g) is 49 at 230°C. If 0.70 mol of PCl3 is added to 0.70 mol

Ymorist [56]

Answer : The correct option is, (B) 0.11 M

Solution :

First we have to calculate the concentration $PCl_3$ and $Cl_2$ .

$\text{Concentration of }PCl_3=\frac{\text{Moles of }PCl_3}{\text{Volume of solution}}$

$\text{Concentration of }PCl_3=\frac{0.70moles}{1.0L}=0.70M$

$\text{Concentration of }Cl_2=\frac{\text{Moles of }Cl_2}{\text{Volume of solution}}$

$\text{Concentration of }Cl_2=\frac{0.70moles}{1.0L}=0.70M$

The given equilibrium reaction is,

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

Initially 0.70 0.70 0

At equilibrium (0.70-x) (0.70-x) x

The expression of $K_c$ will be,

$K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}$

$K_c=\frac{(x)}{(0.70-x)\times (0.70-x)}$

Now put all the given values in the above expression, we get:

$49=\frac{(x)}{(0.70-x)\times (0.70-x)}$

By solving the term x, we get

$x=0.59\text{ and }0.83$

From the values of 'x' we conclude that, x = 0.83 can not more than initial concentration. So, the value of 'x' which is equal to 0.83 is not consider.

Thus, the concentration of $PCl_3$ at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M

The concentration of $Cl_2$ at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M

The concentration of $PCl_5$ at equilibrium = x = 0.59 M

Therefore, the concentration of $PCl_3$ at equilibrium is 0.11 M

3 0

3 years ago

Plz answer plzplzpzlpl

astraxan [27]

Whats the question tho?

8 0

2 years ago

*Riddle!* *Riddle!!* *Riddle!!!*

otez555 [7]

Answer:

https://www.getriddles.com/science-riddles/

Explanation:

go to this link, you will find some answers

hope it helps!

5 0

2 years ago

6. According to the ideas of Democritus and Dalton, which of the following

Varvara68 [4.7K]

Answer: The wire is still copper and does not change by cutting it

Explanation:

Democritus postulated that all materials were composed of these tiny particles called as "atomos".

Daltons postulates are:.

1. All matter is made of very tiny particles called atoms.

2. Atoms is indivisible.

3. Atoms of a given element are identical in mass and chemical properties.

4. Atoms of different elements have different masses and chemical properties.

5. Atoms combine in the ratio of small whole numbers to form compounds.

6. The relative number and kinds of atoms are constant in a given compound.

Thus when copper wire is cut into the smallest possible pieces, the atoms were intact as they are indivisible and all atoms have same mass and chemical properties.Thus the wire is still copper and does not change by cutting it

4 0

3 years ago