Determine la temperatura Kelvin de 2.49 moles de gas contenido en un

1 answer:

7 0

La temperatura del gas contenido en el recipiente es de -259,35 ° C
Explicación:
Para encontrar la unidad de grados en Celsius (° C) en este caso, se usa la ecuación de la ley de los gases ideales.
PV = nRT
Donde P es la presión, V es el volumen, T es la temperatura, n es el número de moles y R es la constante universal de los gases.
P = 143 kPa = 1,4113 atmósferas
V = 2,00 L
n = 2,49 mol
R = 0.08205746 atm * L / mol * K
Resolver para T sería: PV / nR
T = (1.4113 atm * 2.00 L) / (2.49 mol * 0.08205746 atm * L / mol * K)
T = 2,8226 / 0,2043
T = 13,8 K = -259,35 ° C

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Data Given:

Time = t = 30.6 s

Current = I = 10 A

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Solution:
According to Faraday's Law,

W = I t e / F

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Answer:

1) When 6.97 grams of sodium(s) react with excess water(l), 56.0 kJ of energy are evolved.

2) When 10.4 grams of carbon monoxide(g) react with excess water(l), 1.04 kJ of energy are absorbed.

Explanation:

1) The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g).

2 Na(s) + 2H₂O(l) ⇒ 2NaOH(aq) + H₂(g) ΔH = -369 kJ

The enthalpy of the reaction is negative, which means that 369 kJ of energy are evolved per 2 moles of sodium. The energy evolved for 6.97 g of Na (molar mass 22.98 g/mol) is:

$6.97g.\frac{1mol}{22.98g} .\frac{-369kJ}{2mol} =-56.0kJ$

2) The following thermochemical equation is for the reaction of carbon monoxide(g) with water(l) to form carbon dioxide(g) and hydrogen(g).

CO(g) + H₂O(l) ⇒ CO₂(g) + H₂(g) ΔH = 2.80 kJ

The enthalpy of the reaction is positive, which means that 2.80 kJ of energy are absorbed per mole of carbon monoxide. The energy evolved for 10.4 g of CO (molar mass 28.01 g/mol) is:

$10.4g.\frac{1mol}{28.01g} .\frac{2.80kJ}{mol} =1.04kJ$