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3 years ago

6

Determine la temperatura Kelvin de 2.49 moles de gas contenido en un

1 answer:

andrew-mc [135]3 years ago

7 0

La temperatura del gas contenido en el recipiente es de -259,35 ° C
Explicación:
Para encontrar la unidad de grados en Celsius (° C) en este caso, se usa la ecuación de la ley de los gases ideales.
PV = nRT
Donde P es la presión, V es el volumen, T es la temperatura, n es el número de moles y R es la constante universal de los gases.
P = 143 kPa = 1,4113 atmósferas
V = 2,00 L
n = 2,49 mol
R = 0.08205746 atm * L / mol * K
Resolver para T sería: PV / nR
T = (1.4113 atm * 2.00 L) / (2.49 mol * 0.08205746 atm * L / mol * K)
T = 2,8226 / 0,2043
T = 13,8 K = -259,35 ° C

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