Answer:
The enthalpy of the nitrogen-nitrogen bond in N2H4 is 162.6 kJ
Explanation:
For the reaction: N2H4(g)+H2(g)→2NH3(g), the enthalpy change of reaction is
ΔH rxn = 2 ΔHºf NH3 - ΔHºf N2H4
but we also know that the ΔH rxn is calculated by accounting the sum of number of bonds formed and bonds broken as follows:
ΔH rxn = 6H (N-H) + 4 (N-H) + 2H (H-H)
where H is the bond enthalpy .When bonds are broken H is positive, and negative when formed, in the product there are 6 N-H bonds , and in the reactants 4 N-H and 1 H-H bonds).
Consulting an appropiate reference handbook or table the following values are used:
ΔHºf (NH3) = -46 kJ/mol
ΔHºf (N2H4) = 95.94 kJ/mol
(The enthalpy of fomation of hydrogen in its standard state is zero)
H (N-H) = 391 kJ
H (H-H) = 432 kJ
H (N-N) = ?
So plugging our values:
ΔH rxn = 2mol ( -46.0 kJ/mol) - 1mol(95.4 kJ/mol) = -187.40 kJ
-187.40 kJ = 6(-391 kJ) + 4 (391 kJ) + 432 + H(N-N)
-187.40 kJ = -350 kJ + H(N-N)
H(N-N) = 162.6 kJ
A. only volume (cm^3)
Explanation:
The independent variable is typically represented as x. It is the variable that you change during the experiment. In this graph, as volume increases, it increases the mass too. Hope this helps!
Answer:
[ N₂(g) ] = 0.016 M
Explanation:
N₂(g) + 3 H₂(g) ↔ 2 NH₃(g)
The equilibrium constant for the above reaction , can be written as the product of the concentration of product raised to the power of stoichiometric coefficients in a balanced equation of dissociation divided by the product of the concentration of reactant raised to the power of stoichiometric coefficients in the balanced equation of dissociation .
Hence ,
Kc = [ NH₃ (g) ]² / [ N₂(g) ] [ H₂(g) ]³
From the question ,
[ NH₃ (g) ] = 0.5 M
[ N₂(g) ] = ?
[ H₂(g) ] = 2.0 M
Kc = 2
Now, putting it in the above equation ,
Kc = [ NH₃ (g) ]² / [ N₂(g) ] [ H₂(g) ]³
2 = [ 0.5 M ]² / [ N₂(g) ] [ 2.0 M ]³
[ N₂(g) ] = 0.016 M .
Answer: The conc. of products shall increase to nullify the effect of change in concentration. For this purpose, equilibrium would shift to right.
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Reason:
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According to Le Chatelier's principle: "If a chemical system at equilibrium experiences a change in concentration, temperature, volume, or partial pressure, then the equilibrium shifts to counteract the imposed change and a new equilibrium is established."
<span>So, more reactant (weak acid or weak base) would result in shift of equilibrium towards right (i.e. toward products). Hence, the conc. of products would increase so that new equilibrium could be established.</span>
