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polet [3.4K]
3 years ago
6

How many moles of MgCl2 will be produced from 32.0 of Mg(OH)2

Chemistry
1 answer:
vekshin13 years ago
6 0
1.12 miles of MgCl2 will be produced from the 32.0 of Mg(OH)2
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Run clothes washer only when its full
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3 years ago
How much energy is used to melt 44.33 g of solid oxygen?
Nutka1998 [239]

Answer:

Q1 = C * m * dT

Q2 = Qm * m

Qtotal = Q1 + Q2

Q1 - is amount of energy you need to apply to heat oxygen from the current temperature till you reach the melting temperature. Only if the oxygen is below to melting temperature.

C - is calorific capacity of oxygen -- better look at tables, it is a constant value

m - is the amount of oxygen, we will use moles because the other data shows moles, but could be grams, kg, etc.

dT - is the diference of temperatures between the current and the melting one. The melting temperature is constant and you can find it on tables, then (Tm - To)

Q2 is the amount of energy you have to add to melt oxygen once the oxygen has reached the melting temperature (Tm)

Qm is a constant value you could find on tables, depends on the mass of oxygen and is due to internal processes as changes in atomic distributions

If the oxygen is initially at melting temperature (melting point) you only need to know Q2, as dT = 0

I will do an example for you, but in future you should provide data of constants, it takes very long to find them in books or internet.

Data from tables

Tm =  54.36 K

C = 29.378 J/mol K this is at 25 C (or 298 K), is not really correct, you should look at its value at less than 54.36 K, but you can use it here.

Qm = 0.444 kJ/mol

Problem -- you have 44.33g of Oxygen -- Molecular weight of O2 is 32 g/mol

So you have 44.33/32 = 1.385 moles of oxygen

a) if oxygen is already at melting temperature: you only have to melt it

Qtotal = Q1 + Q2 = [0 (dT = 0) + Qm * m] = 0.444 * 1.385 = 0.615 kJ = 615 J

b) supposing an initial temperture of 50 K: now you have to heat oxygen till melting temperature and then melt it.

Q1 = C * m * dT = 29.378 * 1.385 * (54.36 - 50) = 177.442 J

Q2 = Qm * m = 615 J

Qtotal = 177.442 + 615 = 792.44 J

Explanation:

4 0
3 years ago
Read 2 more answers
A ball is moving at a speed of 6.70 m/s. If the kinetic energy of the ball is 3.10 J, what is the mass of the ball?​
Anni [7]

Answer:

<h2>0.14 kg</h2>

Explanation:

The mass of the ball can be found by using the formula

m =  \frac{2k}{ {v}^{2} }  \\

v is the velocity

k is the kinetic energy

From the question we have

m =  \frac{2(3.10)}{ {6.70}^{2} }  =  \frac{6.20}{44.89}  \\  = 0.138115...

We have the final answer as

<h3>0.14 kg</h3>

Hope this helps you

7 0
3 years ago
Identify whether the description refers to a monomer, a polymer, or both. Macromolecule:
larisa86 [58]

Answer:

Macromolecule: polymer

Repeating units: monomer

Simple molecule: monomer

Covalent bonds: both

Explanation:

A macromolecule is a very large molecule commonly created by the polymerization of smaller subunits called monomers. They are typically composed of thousands of atoms or more.

A  monomer is a molecule that can be reacted together with other monomer molecules to form a larger polymer chain.

Polymers include bounds between nonmetal atoms, therefore, they are joint by covalent bonds

3 0
3 years ago
Read 2 more answers
When 0.560 g of na(s) reacts with excess f2(g) to form naf(s), 13.8 kj of heat is evolved at standard-state conditions. what is
sergejj [24]
Enthalpy of formation is the alteration in enthalpy for the formation of one mole of the compound; hence you just have to modify the data you have proportionately to what it would be for one mole of the compound. 
Begin with the balanced equation first, just to safeguard the coefficient on the substance you're given is 1, remembering that the coefficient on your product must be 1. 
Na + (1/2)F2 --> NaF So no problem, since the coefficient of Na is 1. Change the mass of Na you're given to moles: (0.560 g Na)(1 mol Na/22.99 g Na) = 0.0244 mol Na. So, 13.8 kJ heat is altered by the response of 0.0244 mol Na.To look for the heat evolved by 1 mol Na, just divide the amount of heat by the number of moles: 13.8 kJ/0.0244 mol which gives 566.5 kJ/mol. Lastly, whether the heat is changed or obligatory to control the sign of ΔH. Heat is evolved here, meaning the reaction is exothermic, so ΔH = -566 kJ/mol.
8 0
3 years ago
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