All categories

2 years ago

How many moles of MgCl2 will be produced from 32.0 of Mg(OH)2

Chemistry

1 answer:

vekshin12 years ago

6 0

1.12 miles of MgCl2 will be produced from the 32.0 of Mg(OH)2

You might be interested in

Which choice contains a FALSE statment? A. For the vaporization of liquid benzene ΔH is positive. B. For the formation of 1 mol

ser-zykov [4K]

Answer:

B is False

Explanation:

In physical chemistry we always look from system's perspective, so if we heat something ΔH is positive and if the system gives heat out then ΔH is negative.

A. We have to give energy to benzene to evaporate it. Statement true.

B. If heat is absorbed then the enthalpy must be positive.

C. The heat is absorbed then ΔH is positive.

D. Usually for burning heat is exposed from system. So enthalpy is negative.

E. Obvious

7 0

2 years ago

Why do you think there was a rush to mass-produce penicillin around the time of World War II?

Vladimir79 [104]

Answer:

penicillin could protect mice against infection from deadly Streptococci.

Explanation:

5 0

2 years ago

Read 2 more answers

Which of the atoms shown has an atomic number of 4?

spin [16.1K]

Answer:

B. Be

Explanation:

8 0

2 years ago

Which of the following sets are isoelectronic (i.e., have the same number of electrons)? i. Br-, Kr, Sr2+ ii. C, N-, O2- iii. Mg

il63 [147K]

Answer:

ii. $C,\ N^-,\ O^{2-}$

Explanation:

Isoelectric species are the species which have same number of electrons.

From the given options:-

$C,\ N^-,\ O^{2-}$ are the isoelectric species.

All the three species have same number of electrons which is equal to 6.

Carbon has 6 electrons.

$N^-$ has 6 electrons.

$O^{2-}$ has 6 electrons.

8 0

2 years ago

"A crosslinked copolymer consists of 57 wt% ethylene (C2H4) repeat units and 43 wt% propylene (C3H6) repeat units. Determine the

ch4aika [34]

Explanation:

Percentage ethylene by weight = 57%

Percentage propylene by weight = 43%

Suppose in 100 grams of polymer:

Mass of ethylene = 57 g

Mass of propylene = 43 g

Moles of ethylene = $\frac{57 g}{28 g/mol}=2.036 mol$

Moles of propylene = $\frac{43g}{42g/mol}=1.024 mol$

1 mole = $N_A =6.022\times 10^{23}$ molecules/ atoms

Units of ethylene = $2.036 mol\times N_A$

Units of propylene = $1.024 mol\times N_A$

a) Fraction of ethylene units:

$=\frac{2.036 mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{509}{765}$

b ) Fraction of propylene units:

$=\frac{1.024mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{256}{765}$

3 0

2 years ago