All categories

2 years ago

If the volume of the cylinder is to be calculated, what would be the total standard deviation of the volume?

1 answer:

8 0

first calculate the partial derivatives of the two fromulas for each measured variable. Then you calculate the sum of the products of the errors (Dr, DR, and dh) with the squared corresponding partial derivative.and or the deviation

Example for the length of the mantle:

dm/dR = (R-r)/root(w)

dm/dr = -(R-r)/root(w)

dm/dh = h/root(w)

where w = (R-r)²+h². The squared derivatives are

(dm/dR)² = (R-r)²/w

When it comes to statistics and probability theory, standard deviation is used. It demonstrates the accuracy of your data and is used to measure both variability and diversity.

Standard deviation is calculated by taking the square root of the variance. In contrast to a high standard deviation, which indicates that the entered data points are most likely farther from the mean, a low standard deviation indicates that the entered data points are most likely closer to the mean

to learn more about deviation:

brainly.com/question/16555520

#SPJ4

You might be interested in

A __ allows you to determine the position of an object <br><br>this is science plz helpp

Alex_Xolod [135]

The correct answer is C

8 0

3 years ago

When the velocity of the car is constant the force of friction is?

miv72 [106K]

..... equal to the force from the engine pushing the car forward.

That's why the car is not accelerating. The horizontal forces on it
are balanced.

6 0

3 years ago

Drag each tile to the correct box. Arrange the steps in order to describe what happens to a gas when it cools. The particles of

vredina [299]

Answer:

Ok, as the gas starts to cool down, the kinetic energy of the particles starts to decrease, so the first thing that happens is:

"the gas loses thermal energy" (as the gas cools down, the temperature decreases, so it loses thermal energy)

Now, the kinetic energy must decrease, so now:

"the particles of gas move slower".

Then, as the particles start to move slower, they start to get closer to eachother, then we have:

"The space between the gas particles decreases."

As the particles start to get close to eachother, the density of the gas starts to increase, until a point where we get to the condensation point, here we have a change of phase and the gas changes to a liquid, so here we have:

"The gas changes to a liquid."

4 0

3 years ago

Which of the following tools should a scientist use to measure an object in milligrams? a.Electronic balance b.Pan balance .c.Ta

QveST [7]

Answer:

c. Tape measure.

Explanation:

Here in this case we have to measure the length of the object ( distance) so we need to use tape measure.

Tape measure is a device used to measure small distances. It consists of ribbon of clothes, plastic , fiber. glass or metal strip with linear measurement markings. rest all options do not measure length.

7 0

3 years ago

Read 2 more answers

Two small spheres assumed to be identical conductors are placed at 30 cm from each other on a horizontal axis. the first S1 is l

charle [14.2K]

a) The electric force exerted by S1 on S2 is 21.58μN.

In this case we are talking about two different types of charges, a positive charge and a negative charge, therefore, they are sensing a force of attraction.

The magnitude of the force is determined by using the following formula:

$F_{e}=k_{e}\frac{|q_{1}||q_{2}|}{r^{2}}$

where:

= Electric force [N]

= Electric constant ()

= First charge [C]

= Second charge [C]

r = distance between the two charges

So, in this case, the force can be calculated like this:

$F_{e}=(8.99x10^{9}N\frac{m^{2}}{C^{2}})\frac{|12x10^{-9}C||18x10^{-9}C|}{(30x10^{-2}m)^{2}}$

So the force will be equal to:

$F=21.58x10^{-6}N$

which is the same as:

$F=21.58 \micro N$

b) The electric field created by S1 at the level of S2 is $1.20 \frac{kN}{C}$

The electric field tells us how many Newtons of force can be applied on a given point in space per unit of charge caused by an existing electric charge. From the concept, we can take the following formula for the electric field.

$E_{S1}=\frac{F_{e}}{q_{2}}$

where:

= electric field generated by the first sphere.

$E_{S1}=\frac{1.20 x10^{-6}N}{18x10^{-9}C}$

which yields:

$E_{S1}=1.20x10^{3} \frac{N}{C}$

$E_{S1}=1.20 \frac{kN}{C}$

When talking about electric fields, we know what their direction is if we suppose the electric field is always affecting a positive charge in the given point in space. In this case, since S1 is positive, we can asume the electric field is in a direction away from S1.

The electric potential created by S1 at the level or S2 is 360V

Electric potential is defined to be the amount of energy you will have at a given point per electric charge. This electric potential can be found by using the following formula:

V=Er

Where V is the electric potential and it is given in volts.

Volts are defined to be 1 Joule per Coulomb. Energy by electric charge.

So we can use the data found in the previous sections to find the electric potential:

$V=(1.20x10^{3} \frac{N}{C})(30x10^{-2}m)$

V=360V

d) The force exerted by S2 on S1 will be the same in magnitude as the force exerted by S1 on S2 but oposite in direction. This is because the force will depend on the two charges, and the distance between them, so:

The electric force exerted by S1 on S2 is 21.58μN.

The magnitude of the force is determined by using the following formula:

$F_{e}=k_{e}\frac{|q_{1}||q_{2}|}{r^{2}}$

$F_{e}=(8.99x10^{9}N\frac{m^{2}}{C^{2}})\frac{|12x10^{-9}C||18x10^{-9}C|}{(30x10^{-2}m)^{2}}$

So the force will be equal to:

$F=21.58x10^{-6}N$

which is the same as:

$F=21.58 \micro N$

e) The electric field generated by S1 in the middle of S1 and S2 is $4.79 \frac{kN}{C}$

In order to find the electric field generated by S1, we can make use of the following formula

$E=k_{e} \frac{q_{1}}{r_{1}^{2}}$

$E=(8.99x10^{9} N\frac{m^{2}}{C^{2}})(\frac{12x10^{-9}C}{(15x10^{-2}m)^{2}})$

which yields:

$E=4.79 \frac{kN}{C}$

f) The electric field in the middle of S1 and S2 is $11.99 \frac{kN}{C}$

In order to find the electric field generated by two different charges at a given point is found by using the following formula:

$E=k_{e} \sum \frac{q_{i}}{r_{i}^{2}}$

where:

$q_{i}$ = each of the charges in the system

$r_{i}$ = the distance between each of the charges and the point we are analyzing.

Since the electric field is a vector, we need to take into account the individual electric fields' directions. In this case we suppose we have a positive test charge between the two charges. We can see that the positive test charge will sense a force in the same direction independently on if the force is excerted by the positive charge or the negative charge. Therefore both electric fields will have the same direction. We'll suppose the electric fields will be positive then, so:

$E=(8.99x10^{9} N\frac{m^{2}}{C^{2}})[\frac{12x10^{-9}C}{(15x10^{-2}m)^{2}}+\frac{18x10^{-9}C}{(15x10^{-2}m)^{2}}]$

which yields:

$E=11.99 \frac{kN}{C}$

g) The electric potential in the middle of S1 and S2 is 1.80 kV

Since we know what the electric field is from the previous question, we can make use of the same formula we used before to find the electric potential in the middle of S1 and S2

So let's take the formula:

V=Er

So we can use the data found in the previous sections to find the electric potential:

$V=(11.99x10^{3} \frac{N}{C})(15x10^{-2}m)$