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3 years ago

Experiencing a green afterimage of a red object is most easily explained by

Physics

2 answers:

Sonja [21]3 years ago

6 0

Answer:

opponent process theory.

Explanation:

Experiencing a green afterimage of a red object is most easily explained by using opponent process theory.

The opponent process theory suggests that one color pair dominates the other color. For instance we often see yellowish-greens and reddish-yellows, however, we never see reddish-green or yellowish-blue colors. The hypothesis was originally suggested in the late nineteenth's century by the German physiologist Ewald Hering.

il63 [147K]3 years ago

4 0

Answer:

The opponent-process theory

Explanation:

The opponent process theory is based on the human visual system and according to the theory the interpretation of the color is done by the photo-receptors rods and cones in the human eye.

This theory states that the perception of color is governed by the two opponent system which includes - a red-green, a blue-yellow and a black-white mechanism.

Any activity in one of these restricts the activity in the other.

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Teachers are interested in knowing what study techniques their students are utilizing. The researchers randomly select every 10t

uranmaximum [27]

Answer:

Simple Random Sample (SRS)

Explanation:

5 0

3 years ago

. Inside a laser apparatus, the stimulation and relaxation of electrons in atoms causes many photons with the same to be continu

mrs_skeptik [129]

Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same wavelength to be continuously emitted.

From the questions given, the main objective is to fill in the gaps and add important information where necessary. The missing information is highlighted in bold and underlined.

Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same wavelength to be continuously emitted.

2. When these photons are emitted, they travel between two reflective

surfaces to form the wave that is represented in the simulation.

3. This wave is the summation of all the photons being introduced with

every oscillation, and as they continue to travel, the amplitude

increases. 

4. This occurs because the photons are emitted in a coherent fashion;

however, amplitude when the photons overlap in an incoherent

fashion.

5. In a laser device, a small portion of photons are permitted to escape

(for use in an application). This is emulated in the simulation, by

settling the Damping to Lots such that amplitude remains relatively

constant when compared to damping of None. (Damping

represents the Loss of photons.

6. The generation of multiple wavelengths is possible in some laser

producing systems, and the diffraction angle can be varied to allow

the isolation of different wavelengths.

7. Finally, when the power of a laser is described, the wave property

that is being referenced is a function of its frequency and

amplitude.

Therefore, we can conclude that we've fully understood the concept of emission of photons and wavelength in a laser apparatus.

Learn more about wavelength here:

brainly.com/question/23023103?referrer=searchResults

5 0

2 years ago

Assume that the function x(t) represents the length of tape that has unwound as a function of time. find θ(t), the angle through

bekas [8.4K]

We know that arc length (x(t)) is given with the following formula:
$x(t)=\theta(t) r$
Where r is the radius of the barrel. We must keep in mind that as barrel rolls its radius decreases because less and less tape is left on it.
If we say that the thickness of the tape is D then with every full circle our radius shrinks by d. We can write this down mathematically:
$r(\theta)=r_0-\frac{D\cdot \theta}{2\pi}$
When we plug this back into the first equation we get:
$x(t)=\theta(r_0-\frac{D\theta}{2\pi}})\\ \frac{D\theta^2}{2\pi}-\theta r_0+x(t)=0\\$
We must solve this quadratic equation.
The final solution is:
$\theta=\frac{\pi r_0+\sqrt{\pi \left(-2Dx(t)+\pi r_0^2\right)}}{D},\:\theta=\frac{\pi r_0-\sqrt{\pi \left(-2Dx(t)+\pi r_0^2\right)}}{D}$
It is rather complicated solution. If we asume that the tape has no thickness we get simply:
$x(t)=\theta(r_0-\frac{D\theta}{2\pi}});D=0\\
x(t)=\theta r_0\\
\theta(t)=\frac{x(t)}{r_0}$

8 0

4 years ago

Rephrase the law of universal gravitation

IRISSAK [1]

The law of universal gravitation says that one object attracts every other object using a proportional force to the mass of the object.

5 0

3 years ago

What is the cause of most waves and how can this change waves' characteristics?

Tanzania [10]

There are three main factors that affect wave formation: wind velocity, fetch, and duration.

Waves are most commonly caused by wind. Wind-driven waves, or surface waves, are created by the friction between wind and surface water. As wind blows across the surface of the ocean or a lake, the continual disturbance creates a wave crest.

8 0

3 years ago

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