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SCORPION-xisa [38]
2 years ago
14

In this project, you will practice calculating work and speed using the proper formula. You will also use a data table to record

and analyze your data. For each question, you will complete a row in your data table to record the details, and your results. Don't forget to use proper units of measurements in all of the parts of your table!
pls help asap mark brainyist can't spell sorry
Chemistry
2 answers:
Gala2k [10]2 years ago
6 0

Answer:

What is the project about ?

Explanation:

kirill115 [55]2 years ago
4 0

Answer:

I don't understand what your project is about do you have any ss/ Screenshots?

Explanation:

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The boiling point elevation of an aqueous sucrose is found to be 0.39 Celsius. What mass of sucrose (molar mass = 342.30g/mol) w
FromTheMoon [43]

Answer:

130 g of sucrose

Explanation:

Boiling point elevation formula → ΔT = Kb . m

ΔT = Boiling T° solution - Boiling T° pure solvent → 0.39°C

0.39°C = 0.513°C/m . M

m = 0.760 mol/kg → molality = moles of solute / 1kg of solvent

Let's determine the moles of solute → molality . kg

0.760 mol/kg. 0.5 kg = 0.380 moles

If we convert the moles to mass, we'll get the answer

0.380 mol . 342.30 g/mol = 130g

7 0
3 years ago
Which type of star has the greatest temperature on the HR diagram? Question 7 options: Red Supergiants Main Sequence White Dwarf
Sauron [17]

Answer:

Red supergiant

Explanation:

Their core is the hottest.

plz mark me as brainliest.

7 0
3 years ago
Jwjajajahwhab a a skwiwiwiahah​
FrozenT [24]
Thank you :))) for the points have a great day
8 0
3 years ago
Read 2 more answers
How many milliliters of a 8.20 m licl solution contain 18.4 g of licl?
Dovator [93]
Your final answer is that you will need 52.9mL of the 8.20 M of LiCl

3 0
3 years ago
Which is the limiting reagent in the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? Reaction: Na2
NemiM [27]

Answer:

CuSO4

Explanation:

Na2S + CuSO4 → Na2SO4 + CuS

The reaction is balanced (same number of elements in each side)

To determine limiting reagent you need to know the moles you have of each.

Molar mass Na2S = 23 * 2 + 32 = 78

Molar mass CuSO4 = 63.5 + 32 + 16 * 4 = 159.5

Na2S mole = 15.5 / 78 = 0.2

CuSO4 mole = 12.1/159.5 = 0.076

*Remember mole = mass / MM

With that information now you have to divide each moles by its respective stoichiometric coefficient

Na2S stoichiometric coefficient : 1

Na2S : 0.2 / 1 = 0.2

CuSO4 stoichiometric coefficient: 1

CuSO4: 0.076 / 1 = 0.076

The smaller number between them its the limiting reagent, CuSO4

8 0
4 years ago
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