Answer:
r = 5.5 ohms
Explanation:
Given:-
- The open circuit voltage, Vo = 3.5 V
- The terminal voltage, Vt = 2.8 V
- The load, R = 22 ohms
- The internal resistance = r
Find:-
What is the generator’s output impedance (pure resistance)?
Solution:-
- We see that the source Voltage (Vo) is not entirely used for the attached load. Some of the source voltage is dropped within due to the source internal resistance or impedance.
- The terminal voltage (Vt) is the amount of Voltage drop across the load. The current drawn by the load I can be determined by Ohm's Law:
Vt = I*R
I = Vt / R
I = 2.8 / 22
I = 0.12727 Amps
- Since, the attached load (R) and the pure impedance (r) of the source are in series. The current ( I ) is constant across both. The potential drop across the pure resistance (r) can be determined from Ohm's law:
Vo - Vt = I*r
r = ( Vo - Vt ) / I
r = ( 3.5 - 2.8 ) / 0.12727
r = 5.5 ohms
Answer:
See Explanation Below
Explanation:
Given
S → aSb | bY | Y a
Y → bY | aY | ε
Giving a simple description of L(G) in English. The description is as follows;
This means that L(G) contains a string of a's and b's such that the following are true;
1. the string starts with n a’s and m b’s, where n and m can be zero, but not at the same time,and at least one of option 2 and option 3
2. and has any number of a’s or b’s followed by an a
3. ab followed by any number of a’s and b’s
Note that n and m represent numerical digits
Using the description to give a CFG for L(G), the complement of L(G) is written as L'(G)
L'G are elements not in L(G) and they are
L'(G) =a^n b (a∪b) * b^n ∪ a^n (a∪b) * ab^n
Answer:
#Selling vehicles
import locale
locale.setlocale( locale.LC_ALL, 'en_CA.UTF-8' )
#Declaration of variables
total_pay=0
total_sales=0
#Selling details
for i in range(0,2):
#Ask the type of sell
type=input("Enter the type of the car you sold(used/new)? ")
#Check error
while(type.upper()!="USED" and type.upper()!="NEW"):
print('ERROR!!!Should be used or new!!Please Re-enter')
type=input("Enter the type of the car you sold(used/new)? ")
#Input price of the car
price=float(input("Enter the price of the car: "))
#Calculations
if(type.upper()=="NEW"):
total_pay+=1500
else:
total_pay+=price*.05
total_sales+=price
#Display results
print('Total Pay of the sale person = ',locale.currency(total_pay))
print('Total Sales = ',locale.currency(total_sales))
Answer:
22.90 × 10⁸ kg
Explanation:
Given:
Diameter, d = 0.02 m
ωₙ = 0.95 rad/sec
Time period, T = 0.35 sec
Now, we know
T= 
where, L is the length of the steel cable
g is the acceleration due to gravity
0.35= 
or
L = 0.0304 m
Now,
The stiffness, K is given as:
K = 
Where, A is the area
E is the elastic modulus of the steel = 2 × 10¹¹ N/m²
or
K = 
or
K = 20.66 × 10⁸ N
Also,
Natural frequency, ωₙ = 
or
mass, m = 
or
mass, m = 
mass, m = 22.90 × 10⁸ kg
Answer:
0.89 cos (st +116.57°v)
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
