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kodGreya [7K]
2 years ago
5

A 32.50-g sample of a solid is placed in a flask. Toluene, in which the solid is insoluble, is added to the flask so that the to

tal volume of solid and liquid together is 55.00 mL . The solid and toluene together weigh 58.68 g . The density of toluene at the temperature of the experiment is 0.864 g/mL. What is the density of the solid?
Chemistry
1 answer:
marysya [2.9K]2 years ago
8 0

Answer:

The density of the solid is 1,316 g/mL

Explanation:

The weight of both Toluene and the solid insoluble is 58,68 g. And the weight of the solid is 32,50 g. Thus, weight of toluene is:

58,68 g - 32,50 g = 26,18 g of Toluene

To know how much volume that toluene occupy you must use density thus:

26,18 g of toluene × ( 1 mL / 0,864 g) = 30,30 mL of toluene

The volume of both Toluene and the solid is 55,00 mL and the volume of toluene is 30,30 mL. Thus, the volume of the solid is:

55,00 mL - 30,30 mL = 24,70 mL

Knowing both volume and weight it is possible to know the density thus:

32,50 g / 24,70 mL = 1,316 g/mL

I hope it helps!

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8 0
1 year ago
If equal volumes of 0.1 M HCl and 0.2 M TRIS (base form) are mixed together. The pKa of TRIS is 8.30. Which of the following sta
blondinia [14]

Answer:

option D is correct

D. This solution is a good buffer.

Explanation:

TRIS (HOCH_{2})_{3}CNH_{2}

if TRIS is react with HCL it will form salt

(HOCH_{2})_{3}CNH_{2} + HCL ⇆   (HOCH_{2})_{3}NH_{3}CL

Let the reference volume is 100

Mole of TRIS is =  100 × 0.2 = 20

Mole of HCL is =  100 × 0.1 = 10

In the reaction all of the HCL will Consumed,10 moles of the salt will form

and 10 mole of TRIS will left

hence , Final product will be salt +TRIS(9 base)

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8.3

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3 years ago
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5 0
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What is the Molar Mass of Cs2SO3?​
Airida [17]

Answer:

345.89 g/mol

Explanation:

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S - 32.07

O - 16.00 × 3 = 48.00

Now add them all together.

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Hope that helps.

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