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12345 [234]
3 years ago
7

When 0.1375 g of solid magnesium is burned in a constant-volume bomb calorimeter, the temperature increases by 1.126°C. The heat

capacity of the bomb calorimeter, determined in a separate experiment, is 3024 J/°C. Calculate the heat given off by the burning magnesium in kJ/mol.
Physics
1 answer:
Bumek [7]3 years ago
6 0

Answer:

-24.76 kJ/mol

Explanation:

given,

mass of solid magnesium burned = 0.1375 g

the temperature increases by(ΔT) 1.126°C

heat capacity of of bomb calorimeter (C_{cal})= 3024 J/°C

heat absorbed by the calorimeter

    q_{cal} = C_{cal}\DeltaT

    q_{cal} = 3024 \times 1.126

    q_{cal} =3405.24\ J

    q_{cal} =3.405\ kJ

heat released by the reaction

    q_{rxn} = -q_{cal}

    q_{rxn} = -3.405\ kJ

energy density will be equal to heat released by the reaction divided by the mass of magnesium

Energy density = \dfrac{-3.405}{0.1375}

Energy density = -24.76 kJ/mol

heat given off by burning magnesium is equal to -24.76 kJ/mol

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Explanation:

Given

\mu =0.14 Pa.s

Volume Flow rate Q=5.3\times 10^{-5} m^3/s

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According to Hagen-Poiseuille Equation

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\Delta P=\frac{128\mu L\cdot Q}{\pi D^4}

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P_{in}=P_{out}+\frac{128\mu L\cdot Q}{\pi D^4}

P_{in}=1.01325\times 10^5+\frac{128\times 0.14\times 37\times 5.3\times 10^{-5}}{\pi\cdot 1.16^4\times 10^{-8}}

P_{in}=1.01325\times 10^5+6.17\times 10^5

P_{in}=7.19\times 10^5

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3 years ago
If the Sun were scaled down to the size of a grapefruit, about how far would you have to walk from our classroom to reach Alpha
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2000 miles.

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3 years ago
Indiana jones (83.5 kg) is running 3.75 m/s when he jumps in a stationary 312 kg mine cart. what is their joint velocity afterwa
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.7917 m/s

Explanation:

This is a conservation of momentum question. You have an object initially at rest (cart) so that object is initially at 0 momentum. Indiana Jones is 83.5 kg and running 3.75 m/s so he starts with a momentum of 313.125 kg * m/s because momentum is equal to mass * velocity. Once the person jumps in the cart, the cart and the person can be considered one object and by conservation of momentum, the momentum of the Indiana-cart system is equal to 313.125 kg * m/s. By that, we can set that momentum equal to the combined mass * joint velocity. So 313.125 = (83.5kg + 312kg) * joint velocity. Then just solve for the velocity. The answer should be smaller than the intial velocity of the person of 3.75 m/s because the mine cart is HUGE at 312kg.

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When a jet lands on an aircraft carrier, a hook on the tail of the plane grabs a wire that quickly brings the plane to a halt be
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The problem seems to be incomplete because there is no question. However, from the problem description, the logical question is to find he acceleration needed by the jet to land on the airplane carrier. The working equation would be:

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Since the jet stops, v₂ = 0. Substituting the values:
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4 years ago
A liquid of density 1200kg/m³ is filled in a beaker upto the depth of 50 cm. calculate the pressure at bottom of the breaker.(g=
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\boxed{\sf Pressure=pgh}

\\ \qquad\quad\sf{:}\dashrightarrow Pressure=1200(0.5)(9.8)

\\ \qquad\quad\sf{:}\dashrightarrow Pressure=600(9.8)

\\ \qquad\quad\sf{:}\dashrightarrow Pressure=5880Pa

6 0
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