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AlladinOne [14]
3 years ago
13

What happens to the rate of the reaction as temperature increases

Chemistry
1 answer:
xenn [34]3 years ago
4 0

Answer:  d. The rate increases because molecules are moving faster.

Explanation:

Rate of reaction is determined by the number of effective collisions which means how many collisions are resulting into products. The molecules must possess a certain minimum energy in order to get converted to products.

Increasing the temperature means more reactant molecules will have sufficient energies to cross the energy barrier and thus the number of effective collisions increases, thus leading to more products and increased rate of reaction.

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The empirical formula for carbohydrates is CH2O. The molecular weight for a particular carbohydrate is 90.09 grams. What is the
baherus [9]
We find the weight of the empirical formula:
12.0107 + 2 x 1.00794 + 15.9994
= 30.03

Now, we divide the molecular weight by the weight of the empirical formula to find the number of times the empirical formula repeats:
90.09 / 30.03
= 3

The formula is 3(CH₂O)
C₃H₆O₃
6 0
3 years ago
Which principle goes against Bohr's theory and why??​
Basile [38]

Answer:

As the Bohr's fixed orbit gives precise information about the radial position and momentum of the orbit, it is against the Heisenberg uncertainty principle. Thus it is inferred that the Heisenberg uncertainty principle goes and the concept Bohr's fixed Orbit are opposite to each other.

Explanation:

7 0
3 years ago
Free-energy change, ΔG∘, is related to cell potential, E∘, by the equationΔG∘=−nFE∘where n is the number of moles of electrons t
mart [117]

Answer:

a)\Delta G=372490 J

b)\Delta G=-568614 J

Explanation:

a) The reaction:

Mg(s) +Fe^{2+}(aq) \longrightarrow Mg^{2+}(aq) + Fe(s)

The free-energy expression:

\Delta G=-n*F*E

E=E_{red}-E_{ox]

The element wich is reduced is the Fe and the one that oxidates is the Mg:

-0.44V=E_{red}-(-2.37V)=1.93V

The electrons transfered (n) in this reaction are 2, so:

\Delta G=-2mol*96500 C/mol * 1.93 V

\Delta G=-372490 J

b) If you have values of enthalpy and enthropy you can calculate the free-energy by:

\Delta G=\Delta H - T* \Delta S

with T in Kelvin

\Delta G=-675 kJ*\frac{1000J}{kJ} - 298K*-357 J/K

\Delta G=-568614 J

7 0
3 years ago
80cm^3 of oxygen gas diffused through a porous hole in 50 seconds how long wiil it take 120cm^3 of nitrogen (iv) oxide to diffus
inysia [295]

Answer: it will take 89.93secs

Explanation:Please see attachment for explanation

5 0
3 years ago
“Fe(NO3)3” is a...
ioda

Answer:

1. Fe(NO3)3 is C. Chemical formula

2. Manganese Sulphate is C. Name

3. Zn is C. Symbol

Hope this helps!

3 0
3 years ago
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