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guapka [62]
3 years ago
7

What statement best describes entrepreneurship?

Computers and Technology
2 answers:
pav-90 [236]3 years ago
6 0

Answer:

D. It requires creativity and ambition.

Explanation:

I took the test :/

RideAnS [48]3 years ago
3 0

D. It requires creativity and ambition. I know its right

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Which studio produced the film The Jazz Singer, the first of many “talkies”?
olga nikolaevna [1]
Warner Brother produced the Jazz Singer. 
8 0
3 years ago
g Write a Racket function (process lst1 lst2) that processes the corresponding elements of the two lists and returns a list. If
blagie [28]

Answer:

  1. def process(lst1, lst2):
  2.    newList = []
  3.    for i in range(0, len(lst1)):
  4.        sum = lst1[i] + lst2[i]
  5.        newList.append(sum)
  6.    return newList
  7. list1 = [1, 3, 5, 7, 9]
  8. list2 = [2, 4, 6, 8, 10]
  9. print(process(list1, list2))

Explanation:

Firstly, create a function process that takes two input lists (Line 1). In the function, create a new list (Line 2). Use a for loop to traverse through the elements of the two lists and total up the corresponding elements and add the sum to the new list (Line 3 - 5). At last, return the new list (Line 6).

In the main program, create two sample list and use them as arguments to test the function process (Line 8 - 9). We shall get the output  [3, 7, 11, 15, 19].

8 0
3 years ago
In this assignment, you will create a flashcard app for teaching addition and multiplication. The student will choose the type o
Anna11 [10]

Answer:

See explaination

Explanation:

import java.util.*;

import java.lang.Math;

public class Main

{

public static double getRandomDoubleBetweenRange (double min, double max)

{

double x = (Math.random () * ((max - min) + 1)) + min;

return x;

}

public static void main (String[]args)

{

int option, number_of_problems, correct_answer;

double max_operand, average =

0, user_answer, sum, first_number, second_number, multiply,

sum_or_multiply;

Scanner user_input = new Scanner (System.in);

do

{

System.out.println

("Choose the type of problem: \n1. Addition \n2. Multiplication \n3. Mixed \n4. Quit");

option = user_input.nextInt ();

switch (option)

{

case 1:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 0; i < number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

System.out.println (first_number + " + " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum = first_number + second_number;

if (sum == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.out.println ("Incorrect, The Correct answer is " +

sum);

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 2:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 0; i < number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

System.out.println (first_number + " * " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

multiply = first_number * second_number;

if (multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.out.println ("Incorrect, The Correct answer is " +

multiply);

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 3:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 1; i <= number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

if (i % 2 == 1)

{

System.out.println (first_number + " + " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum_or_multiply = first_number + second_number;

if (sum_or_multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.

out.println ("Incorrect, The Correct answer is " +

sum_or_multiply);

}

}

else

{

System.out.println (first_number + " * " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum_or_multiply = first_number * second_number;

if (sum_or_multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.

out.println ("Incorrect, The Correct answer is " +

sum_or_multiply);

}

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 4:

System.out.println ("Thanks for playing.");

break;

default:

System.out.println ("Please choose a valid option");

break;

}

}

while (option != 4);

}

}

3 0
3 years ago
Technologies that allow for instant worldwide communication include satellite and computer systems. mobile phones and internet a
maw [93]

Technologies that allow for instant worldwide communication include mobile phones and internet access. Cell phones , wireless devices  and smart phones are technologies that have made global communication instant and more effective.

The internet and the development of digital technology (computer-based technology) in particular, have made the most significant impact on globalization.

3 0
2 years ago
Read 2 more answers
Consider two different implementations, M1 and M2, of the same instruction set. There are five classes of instructions (A, B, C,
r-ruslan [8.4K]

Answer:

Kindly check explanation

Explanation:

Given the table :

Class___M1____M2____frequency

A______1______2______60%

B______2______3______30%

C______4______4______10%

A) Average CPI for each machine M1 and M2:

Frequency * cycles :

For M1:

(60% × 1) + (30% × 2) + (10% × 4)

0.6 + 0.6 + 0.4 = 1.6

For M2:

(60% × 2) + (30% × 3) + (10% × 4)

1.2 + 0.9 + 0.4 = 2.5

Calculate the average MIPS ratings for each machine, M1 and M2.

MIPS = clockrate / average CPI × 10^6

Clock rate for M1 isnt given

However, clock rate for M2 = 3,300

For M2 = (3300/2.5 ×10^6 = 0.00132

7 0
2 years ago
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