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3 years ago

What kind of situation can you think would be a benefit of reducing friction?

Physics

1 answer:

zepelin [54]3 years ago

8 0

Answer:

Wear and tear of an object is not desirable as it reduces its life. This is more so in case of moving parts in automobiles and machinery. Therefore, efforts are made to reduce friction between moving parts. Friction between moving parts is usually reduced by introducing a substance between the moving surfaces.

Explanation:

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Explain why you cannot use mass or volume alone to identify substances.

Alex17521 [72]

Objects can have the same mass (but different <span>compositions). Only mass or volume cannot tell you if the object is solid or vo</span>lumes) or same volume (but different masses)

4 0

3 years ago

How much work was done by a hot air balloon to lift up a 100 Newton to a height of 300 meters?

Monica [59]

So, the work was done by that hot air-balloon is <u>30,000 J or 30 kJ</u>.

<h3>Introduction</h3>

Hi ! In this question, I will help you. <u>Work is the amount of force exerted to cause an object to move a certain distance from its starting point</u>. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :

$\boxed{\sf{\bold{W = F \times s}}}$

With the following condition :

W = work (J)
F = force (N)
s = shift or displacement (m)

Now, the s (displacement) can be written as ∆h (altitude change) because the object move to vertical line. The formula can also be changed to:

$\boxed{\sf{\bold{W = F \times \Delta h}}}$

With the following condition :

W = work (J)
F = force (N)
$\sf{\Delta h}$ = change of altitude (m)

If an object has mass, then the object will also be affected by gravity. Always remember that F = m × g. So that :

$\sf{W = F \times \Delta h}$

$\boxed{\sf{\bold{W = m \times g \times \Delta h}}}$

With the following condition :

W = work (J)
m = mass of the object (kg)
g = acceleration of the gravity (m/s²)
$\sf{\Delta h}$ = change of altitude (m)

<h3>Problem Solving</h3>

We know that :

F = force = 100 N
$\sf{\Delta h}$ = change of altitude 300 m

What was asked :

W = work = ... J

Step by step :

$\sf{W = F \times \Delta h}$

$\sf{W = 100 \times 300}$

$\boxed{\sf{W = 30,000 \: J = 30 \: kJ}}$

<h3>Conclusion</h3>

So, the work was done by that hot air-balloon is 30,000 J or 30 kJ.

Work that he had done to lift object brainly.com/question/26341717
Converting work to potential energy brainly.com/question/26487284

5 0

3 years ago

a coil of 40 henry inductance is connected in series with aresistance of 8ohm and the combination is joined to the terminals of

Andreyy89

Answer: 5 seconds

Explanation:

Given the following :

Inductance (L) = 40 henry

Resistance = 8 ohms

The circuit given above is a Resistor - Inductor (RL) circuit network. The time constant of an RL circuit is the ratio of the circuit Inductance (L) and Resistance (R). Time constant is measured in seconds.

THAT IS;

Time constant = L / R

THEREFORE ;

Time constant = 40 / 8

Time constant = 5 seconds

7 0

3 years ago

Find the energy in joules required to lift a 55.0 megagram object a distance of 500cm

pantera1 [17]

1,000 grams = 1 kilogram
so 55 megagrams = 55,000 kilograms

100 cm = 1 meter
so 500 cm = 5 meters

Acceleration of gravity on Earth = 9.8 m/s²

Weight = (mass) x (gravity)

========================================

Work = increase in potential energy =

   (weight) x (height) =

   (mass) x (gravity) x (height) =

   (55,000 kg) x (9.8 m/s²) x (5 m) =

   2,695,000 joules .

5 0

4 years ago

Please help i’m running out of time to answer

kipiarov [429]

Answer:

5,970 N

Explanation:

m = 597 kg

a = 10 m/s^2

Plug those values into the following equation:

F = ma

F = (597 kg)(10 m/s^2)

F = 5,970 N

4 0

3 years ago