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TEA [102]
3 years ago
13

What kind of situation can you think would be a benefit of reducing friction?

Physics
1 answer:
zepelin [54]3 years ago
8 0

Answer:

Wear and tear of an object is not desirable as it reduces its life. This is more so in case of moving parts in automobiles and machinery. Therefore, efforts are made to reduce friction between moving parts. Friction between moving parts is usually reduced by introducing a substance between the moving surfaces.

Explanation:

You might be interested in
The momentum of a 0.1 kg object traveling at 2000 m/s is 20,000 kg·m/s. True or False
Alina [70]

That's false.  

The definition of momentum is (mass) x (speed), so they must be multiplied.

"20,000 kg-m/s" has the correct units resulting from multiplication, but the number could only be the result of division.

3 0
3 years ago
In what way is a touch screen similar to a CCD? In what way is it different?
kupik [55]
A charge-coupled device (CCD) is a light-sensitive integrated circuit that captures images by converting photons to electrons.

A touch screen is a computer display screen that is also an input device. The screens are sensitive to pressure; a user interacts with the computer by touching pictures or words on the screen.

The similarity is the sensitivity.
The difference is CCD scans or ‘takes images’, whereas touch-screen is where a user interacts with the software.

Hope this helps!
Please give Brainliest!
3 0
2 years ago
The resistance of a wire depends upon the material's resistivity and the length and cross‑sectional area of the wire. What will
andriy [413]

Answer:

R' = 4R

The resistance will become 4 times the initial value.

Explanation:

The resistance of a wire at room temperature, is given by the following formula:

R = ρL/A   ----------- equation 1

where,

R = Resistance of wire

ρ = resistivity of the material

L = Length of wire

A = Cross-sectional area of wire

Now, if the length (L) is multiplied by 4, then resistance will become:

R' = ρ(4L)/A

R' = 4 (ρL/A)

using equation 1:

<u>R' = 4R</u>

<u>The resistance will become 4 times the initial value.</u>

6 0
4 years ago
What is the safest method to determine electrical current
Kisachek [45]
Break the circuit and apace a meter actually within the circuit.
4 0
2 years ago
Two blocks on a frictionless horizontal surface are on a collision course. one block with mass 0.6 kg moves at 0.8 m/s to the ri
Elanso [62]

First we can say that since there is no external force on this system so momentum is always conserved.

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

0.6*0.8 + 1.2*0 = 0.6*v_{1f} + 1.2*v_{2f}

0.48= 0.6*v_{1f} + 1.2*v_{2f}

0.8  = v_{1f} + 2v_{2f}

now by the condition of elastic collision

v_{2f} - v_{1f} = 0.8 - 0[\tex]now add two equations[tex]3*v_{2f} = 1.6

v_{2f} = 0.533 m/s

also from above equation we have

v_{1f} = -0.267 m/s

So ball of mass 0.6 kg will rebound back with speed 0.267 m/s and ball of mass 1.2 kg will go forwards with speed 0.533 m/s.

8 0
4 years ago
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