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Norma-Jean [14]
3 years ago
7

Which ion was fomed by providing the second ionization to remove an electron A) ca2+ B)N3- B)Fe3+ C)S2

Chemistry
1 answer:
zalisa [80]3 years ago
6 0
The <span>ion that is formed by providing the second ionization to remove an electron is </span><span>N3-. The answer is letter B. The rest of the choices do not answer the question above.</span>
You might be interested in
6. 7. A hyperbaric chamber has a volume of 200. L. (a) How many moles of oxygen are needed to fill the chamber at room temperatu
Otrada [13]

Answer:

a) 24.7 mol

b) 790 g

Explanation:

Step 1: Given data

  • Volume of the chamber (V): 200. L
  • Room temperature (T): 23 °C
  • Pressure of the gas (P): 3.00 atm

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 23°C + 273.15 = 296 K

Step 3: Calculate the moles (n) of oxygen

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol

Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen

The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.

m = n × M

m = 24.7 mol × 32.00 g/mol = 790 g

6 0
3 years ago
What is the quantity of heat (in kJ) associated with cooling 185.5 g of water from 25.60°C to ice at -10.70°C?Heat Capacity of S
Cerrena [4.2K]

Taking into account the definition of calorimetry, sensible heat and latent heat,  the amount of heat required is 37.88 kJ.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Sensible heat</h3>

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

  • <u><em>25.60 °C to 0 °C</em></u>

First of all, you should know that the freezing point of water is 0°C. That is, at 0°C, water freezes and turns into ice.

So, you must lower the temperature from 25.60°C (in liquid state) to 0°C, in order to supply heat without changing state (sensible heat).

The amount of heat a body receives or transmits is determined by:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • c= Heat Capacity of Liquid= 4.184 \frac{J}{gC}
  • m= 185.5 g
  • ΔT= Tfinal - Tinitial= 0 °C - 25.60 °C= - 25.6 °C

Replacing:

Q1= 4.184 \frac{J}{gC}× 185.5 g× (- 25.6 °C)

Solving:

<u><em>Q1= -19,868.98 J</em></u>

  • <u><em>Change of state</em></u>

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

In this case, you know:

n= 185.5 grams× \frac{1mol}{18 grams}= 10.30 moles, where 18 \frac{g}{mol} is the molar mass of water, that is, the amount of mass that a substance contains in one mole.

ΔHfus= 6.01 \frac{kJ}{mol}

Replacing:

Q2= 10.30 moles×6.01 \frac{kJ}{mol}

Solving:

<u><em>Q2=61.903 kJ= 61,903 J</em></u>

  • <u><em>0 °C to -10.70 °C</em></u>

Similar to sensible heat previously calculated, you know:

  • c = Heat Capacity of Solid = 2.092 \frac{J}{gC}
  • m= 185.5 g
  • ΔT= Tfinal - Tinitial= -10.70 °C - 0 °C= -10.70 °C

Replacing:

Q3= 2.092 \frac{J}{gC} × 185.5 g× (-10.70) °C

Solving:

<u><em>Q3= -4,152.3062 J</em></u>

<h3>Total heat required</h3>

The total heat required is calculated as:  

Total heat required= Q1 + Q2 +Q3

Total heat required=-19,868.98 J + 61,903 J -4,152.3062 J

<u><em>Total heat required= 37,881.7138 J= 37.8817138 kJ= 37.88 kJ</em></u>

In summary, the amount of heat required is 37.88 kJ.

Learn more about calorimetry:

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7 0
2 years ago
Is Triethylamine water soluble?
nignag [31]
<span>Triethylamine is only slightly soluble in water above 18.7 degrees Celsius!</span>
5 0
4 years ago
A 70.0-g piece of copper metal at 54.0 °C is placed in 50.0 g of water at 26.0 °C. If the final temperature of the water and met
KatRina [158]

The specific heat in, J /g °C of copper is 0.386J/g°C

HOW TO CALCULATE SPECIFIC HEAT CAPACITY OF A SUBSTANCE:

  • The specific capacity of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

Q = quantity of heat absorbed or released (J)

m = mass of substance (g)

∆T = change in temperature (°C)

c = specific heat capacity (J/g°C)

For a colorimeter, the following equation applies:

m.c.∆T (water) = - m.c.∆T (metal)

  • For water:

m = 50g

c = 4.184 J/g°C

∆T = 29.2 - 26°C = 3.2°C

  • For copper:

m = 70g

c = ?

∆T = 29.2 - 54°C = -24.8°C

m.c.∆T (water) = - m.c.∆T (metal)

50 × 4.184 × 3.2 = -(70 × c × -24.8)

669.44 = 1736c

c = 669.44 ÷ 1736

c = 0.386J/g°C

Therefore, the specific heat in, J /g °C of copper is 0.386J/g°C

Learn more at: brainly.com/question/16787162?referrer=searchResults

7 0
2 years ago
Which Has The Largest Value Of The Rate Constant, K? A. Milk Spoiling B. Iron Rusting C. Paint Drying D. Paper Burning
Rina8888 [55]
I think its D hope it helps
4 0
3 years ago
Read 2 more answers
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