Answer: How much heat is required to convert 29 g of ice at -4.0 ˚C to water vapor at 105 ˚C (report your answer to three significant figures)? Answer all five parts, showing your detailed calculations: i) Heat to warm ice from -4.0 to 0 oC: ii) Heat to convert ice to liquid: iii) Heat to warm liquid to boiling: iv) Heat to convert liquid to gas
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Explanation:
e
Answer: maybe 1.4 degrees higher than initial?
Not sure if all the needed info is here, I’m a bit rusty but I just tried to plug it into my calculator and got stuck. Anyway, the equation needed is Q=mcT, Q being energy, m mass, c spec. heat capacity and T as the change in temperature
Answer:
The balance of chemical equation is given below.
3Ca + N2------ Ca3N2
Moles HCl reacted : 0.0135
<h3>Further explanation</h3>
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
So to find the number of moles can be expressed as
n = V x M
The volume of HCl 30 cm³=3.10⁻² dm³
Molarity of HCl = 0.45 mol/dm³
so moles HCl reacted :
