Answer:
Assembler
Explanation:
An assembler can be define as a computer utility program that read, interpret and convert software programs written in low level assembly language into an object file, machine language, code and instruction that can be understood and executed by a computer.
Explanation:
are bhai brainly aap english me questions kar ne ko hai
ye kon si bhasha hai ??????
Answer:
A) About
newtons
B) 76.518 newtons
C) 111.834 newtons
Explanation:
A)
, where G is the universal gravitational constant, M 1 and 2 are the masses of both objects in kilograms, and r is the radius in meters. Plugging in the given numbers, you get:
![F_g=\dfrac{(6.67408 \times 10^{-11})(7.8)(11.4)}{(0.8)^2}\approx 9.273 \times 10^{-9}](https://tex.z-dn.net/?f=F_g%3D%5Cdfrac%7B%286.67408%20%5Ctimes%2010%5E%7B-11%7D%29%287.8%29%2811.4%29%7D%7B%280.8%29%5E2%7D%5Capprox%209.273%20%5Ctimes%2010%5E%7B-9%7D)
B) You can find the weight of each object on Earth because you know the approximate acceleration due to gravity is 9.81m/s^2. Multiplying this by the mass of each object, you get a weight for the first particle of 76.518 newtons.
C) You can do a similar thing to the previous particle and find that its weight is 11.4*9.81=111.834 newtons.
Hope this helps!
Answer:
1. cout << "Num: " << songNum << endl;
2. cout << songNum << endl;
3. cout << songNum <<" songs" << endl;
Explanation:
//Full Code
#include <iostream>
using namespace std;
int main ()
{
int songNum;
songNum = 5;
cout << "Num: " << songNum << endl;
cout << songNum << endl;
cout << songNum <<" songs" << endl;
return 0;
}
1. The error in the first cout statement is that variable songnum is not declared.
C++ is a case sensitive programme language; it treats upper case and lower case characters differently.
Variable songNum was declared; not songnum.
2. Cout us used to print a Variable that has already been declared.
The error arises in int songNum in the second cout statement.
3. When printing more than one variables or values, they must be separated with <<