When a person is turning onto a two-lane road divided by a broken yellow line, you know immediately that you are on a two-way road.
<h3>What is the road about?</h3>
Note that a Yellow centerlines can be seen in roads and it is one that is often used to separate traffic moving in different directions.
Note also that Broken lines can be crossed to allow slower-moving traffic and as such, When a person is turning onto a two-lane road divided by a broken yellow line, you know immediately that you are on a two-way road.
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You are turning onto a two-lane road divided by a broken yellow line. You know immediately that:
Answers
You are on a two-way road.
You are on a one-way road.
The road is under repair.
You must stay to the left of the broken yellow lines.
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D D D D D D D D D D D D D D D DdDdddddf
Answer:
<em>T = 25.41 Nm</em>
Explanation:
Calculating Nsync (Synchronous Speed):
Calculating s (Slip):
![s = (Nsync - Nm) / Nsync \\[tex]s = (3600-2464)/3600\\s = 0.3156](https://tex.z-dn.net/?f=s%20%3D%20%28Nsync%20-%20Nm%29%20%2F%20Nsync%20%5C%5C%3C%2Fp%3E%3Cp%3E%5Btex%5Ds%20%3D%20%283600-2464%29%2F3600%5C%5Cs%20%3D%200.3156)
Calculating Vth (Thevenin Voltage):
Calculating Rth (Thevenin Resistance):
Calculating Xth (Thevenin Reactance):
Xth = Xs = 1.3 ohm
Calculating Torque:
![T = (3Vth^{2}Rr/s) / (Wsync[(Rth+Rr/s)^{2} + (Xth + Xr)^{2}])\\T = (3*205.39*0.7/0.3156) / 377[(2.22+0.7/0.315)^{2} + (1.3+1.8)^{2}]](https://tex.z-dn.net/?f=T%20%3D%20%283Vth%5E%7B2%7DRr%2Fs%29%20%2F%20%28Wsync%5B%28Rth%2BRr%2Fs%29%5E%7B2%7D%20%2B%20%28Xth%20%2B%20Xr%29%5E%7B2%7D%5D%29%5C%5CT%20%3D%20%283%2A205.39%2A0.7%2F0.3156%29%20%2F%20377%5B%282.22%2B0.7%2F0.315%29%5E%7B2%7D%20%2B%20%281.3%2B1.8%29%5E%7B2%7D%5D)
T = 280699 / 377 [19.69 + 9.61]
<em>T = 25.41 Nm</em>
The answer is increases because when something like that decreases it’s always decreasing that probly makes no sense Imao but it’s increases
Answer:
V = 0.00459 ft/s
Explanation:
Since the Piston is moving downwards with a constant velocity V, from the first Newton’s law we know that all vertical forces, must have zero resultant (their sum over vertical axis must equal to zero). Therefore, force that pulls the piston down, is equalized by force of viscous friction Fd= Fvf = 0.5lb (lb here is the pound-force unit). We will relate F ѵ f with τ and from that derive the equation for V.
Fѵf = τ . A
Where τ = µ. du/dy = µ . V/b , and A = π . D . l from this Follows:
Fѵf= (V. A .µ )/b V= ( Fѵf .b )/(A.µ)
Placing all the known values in the equation ( remember to transform inches to feet, by multiplying inches values with the factor 1/12), we obtain :
ft2
V = ((0.5lb) . (0.002/12 ft))/(π . (5.48/12 ft) . (9.50/12 ft) . (0.016 lb.s/(ft^2 )))
V = 0.00459 ft/s
